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Dima020 [189]
3 years ago
3

Most transition metals can exist in more than one oxidation state, and as such, can form oxides with different formulas. If a ba

sic solution containing 1.89 g of dissolved copper(II)chloride dihydrate (molar mass = 170.48 g/mol) is reacted with excess hydrazine, N2H4, a red form of copper oxide is created. If that solid is isolated, it has a mass of 0.79 g after drying. 
What is the formula of this copper oxide?
Did the oxidation state of copper change during this reaction?
Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

- The formula of the formed copper oxide is Cu₂O

- The oxidation state of copper does change from (II) to (I), because copper is reduced.

Explanation:

Hydrazine (N₂H₄) is a well known reducing agent, so it reduces copper(II)chloride (CuCl₂). The oxidation state of Cu in CuCl₂ is +2:

CuCl₂ → Cu²⁺ + 2 Cl⁻

Thus, when Cu²⁺ is reduced to an oxide, it is formed copper(I) oxide (Cu₂O), which is a red solid. According to this, we can conclude:

- The formula of the formed copper oxide is Cu₂O.

- The oxidation state of copper does change from (II) to (I), because copper is reduced.

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{ \bf{PV= \frac{m}{M} RT}} \\  \\ { \tt{(0.65  \times 23.52)  =  \frac{25}{M}  \times 0.081 \times (25 + 273)}} \\  \\ M = 39.5 \: g

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cuz what we are shown in school often fails to foster curiosity in us.

Explanation:

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The boiling point of liquid oxygen is 90.2 k at atmospheric pressure. (a) what is this temperature on the celsius scale?
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3 years ago
You dissolve 3 moles of NaCl into 12 L of water. What is the Molarity?​
DerKrebs [107]

Molarity is moles over liter. When checking for molarity, before diving, make sure the units are correct. In this case, both units are moles and liters, so we can assume the molarity is 3/12, or 0.25 M

3 0
4 years ago
To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
3 years ago
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