Answer:
<em>Details in the explanation</em>
Explanation:
<u>Vertical Launch</u>
When an object is thrown vertically in free air (no friction), it moves upwards at its maximum speed while the acceleration of gravity starts to brake it. At a given time and height, the object stops in mid-air and starts to fall back to the launching point until reaching it with the same speed it was launched.
We are given an expression for the height of an object in function of time t

<em>Please note we have deleted the second 'squared' from the formula since it's incorrect and won't describe the motion of vertical launch.</em>
We now have to evaluate h for the following times, assuming h comes in feet
At t=1 sec

The object is at a height of 48 feet
At t=2 sec

The object is at a height of 64 feet. This is the maximum height the object will reach, as we'll see below
At t=3 sec

The object is at a height of 48 feet. We can clearly see it's returning from the maximum height and is going down
At t=4 sec

The object is at ground level and has returned to the launch point.
Explanation:
this is the ans hope it works
Let's convert the speed of the winds into SI units.
We know that
1 miles = 1609 m
1 hour = 3600 s
So, the velocity written in m/s is
Answer:
<em>The force exerted by the car engine was 3000 N</em>
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Where a is the acceleration of the object.
On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

Where:
vf is the final speed
vo is the initial speed
a is the acceleration
t is the time
The question describes how Meitner drove home taking her car from rest to a speed of 20 m/s in 10 seconds. This provides us the following data:
vf=20 m/s, v0=0 (rest), t = 10 seconds.
From the kinematics equation, we can solve for a:


The force exerted by the car engine was:


The force exerted by the car engine was 3000 N