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kirill115 [55]
3 years ago
11

What type of device forms images by changing the speed at which light

Physics
2 answers:
snow_tiger [21]3 years ago
8 0

Answer:

It's Lens

Explanation: I did the assignment

Nady [450]3 years ago
3 0

Answer:

Any Lens

Explanation:

I Hope it's right if not so Sorry :)

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Fbejfsjnvfdjbesjkbf dsjlbc dsjlc
pav-90 [236]

Answer:

???

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7 0
3 years ago
Read 2 more answers
The periodic table arranges elements by increasing _________.
Olegator [25]

Answer:

Atomic number

Explanation:

Hope it helps you in your learning process.

4 0
3 years ago
A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w
amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

(c) the fraction of the initial energy lost is 0.71

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁  + m₂u₂ = v(m₁  +  m₂)

10 x 3   + 25 x 0   = v(10  +  25)

30  = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\

the final kinetic energy of the package;

K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J

the fraction of the initial energy lost;

= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71

7 0
2 years ago
For a concave mirror, when the object is at focus the image is formed at
Sergeeva-Olga [200]

Answer:

When the object is placed at the focus the image is formed at infinity.

Explanation:

When a ray passes through focus and incident on a concave mirror then it will travel parallel to principal axis after reflection.Hence the image is formed at infinity.

8 0
3 years ago
A ruined in a race decides to accelerate right up to the moment he crosses the line He is the initially travelling at 5m/s and a
docker41 [41]

Answer:

S = V t + 1/2 a t^2 = 5 m/s * 5 s + .2 m/s^2 * 25 s^2 =

25 m + 5 m = 30 m     distance traveled

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6 0
2 years ago
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