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3 years ago

What type of device forms images by changing the speed at which light

Physics

2 answers:

snow_tiger [21]3 years ago

8 0

Answer:

It's Lens

Explanation: I did the assignment

Nady [450]3 years ago

3 0

Answer:

Any Lens

Explanation:

I Hope it's right if not so Sorry :)

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A motorcycle has a mass of 350kg. A force of 1295N is applied to the cycle what is the motorcycles acceleration

Maru [420]

Answer: $3.7 m/s^2$

Explanation:

The acceleration of the motorcycle is given by Newton's second law:

$a=\frac{F}{m}$

where

F = 1295 N is the force applied to the motorcycle

m = 350 kg is the mass of the motorbike

a is the acceleration

By substituting the numbers into the formula, we find

$a=\frac{F}{m}=\frac{1295 N}{350 kg}=3.7 m/s^2$

4 0

3 years ago

Calculate the weight of each of the following masses on earth. Show working

padilas [110]

W=mg

a. W=0.01*9.81=0.0981N
b. W=3.6*9.81=35.316N
c.W=0.713*9.81=6.99453N

6 0

2 years ago

During a test, a NATO surveillance radar system, operating at 37 GHz at 182 kW of power, attempts to detect an incoming stealth

Marta_Voda [28]

(a) $2.68\cdot 10^{-6} W/m^2$

The intensity of an electromagnetic wave is given by

$I=\frac{P}{A}$

where

P is the power

A is the area of the surface considered

For the waves in the problem,

$P=182 kW = 1.82\cdot 10^5 W$ is the power

The area is a hemisphere of radius

$r=104 km=1.04\cdot 10^5 m$

$A=2\pi r^2=2\pi (1.04\cdot 10^5 m)^2=6.8\cdot 10^{10} m^2$

So, the intensity is

$I=\frac{1.82\cdot 10^5 W}{6.8\cdot 10^{10}m^2}=2.68\cdot 10^{-6} W/m^2$

(b) $5.9\cdot 10^{-7} W$

In this case, the area of the reflection is

$A=0.22 m^2$

So, if we use the intensity of the wave that we found previously, we can calculate the power of the aircraft's reflection using the same formula:

$P=IA=(2.68\cdot 10^{-6} W/m^2)(0.22 m^2)=5.9\cdot 10^{-7} W$

(c) $8.7\cdot 10^{-18} W/m^2$

We said that the power of the waves reflected by the aircraft is

$P=5.9\cdot 10^{-7} W$

If we assume that the reflected waves also propagate over a hemisphere of radius

$r=104 km=1.04\cdot 10^5 m$

which has an area of

$A=2\pi r^2=2\pi (1.04\cdot 10^5 m)^2=6.8\cdot 10^{10} m^2$

Then the intensity of the reflected waves at the radar site will be

$I=\frac{P}{A}=\frac{5.9\cdot 10^{-7} W}{6.8\cdot 10^{10} m^2}=8.7\cdot 10^{-18} W/m^2$

(d) $8.1\cdot 10^{-8} V/m$

The intensity of a wave is related to the maximum value of the electric field by

$I=\frac{1}{2}c\epsilon_0 E_0^2$

where

c is the speed of light

$\epsilon_0$ is the vacuum permittivity

$E_0$ is the maximum value of the electric field vector

Solving the equation for $E_0$ ,

$E_0=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(8.7\cdot 10^{-18} W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12} F/m)}}=8.1\cdot 10^{-8} V/m$

(e) $1.9\cdot 10^{-16} T$

The maximum value of the magnetic field vector is given by

$B_0 = \frac{E_0}{c}$

Substituting the values,

$B_0 = \frac{(8.1\cdot 10^{-8} V/m)}{3\cdot 10^8 m/s}=2.7\cdot 10^{-16} T$

And the rms value of the magnetic field is given by

$B_{rms} = \frac{B_0}{\sqrt{2}}=\frac{2.7\cdot 10^{-16} T}{\sqrt{2}}=1.9\cdot 10^{-16} T$

7 0

3 years ago

A steel needle when placed carefully on water can be made to float.when the detergent is added to the water it sink.explain the

Dvinal [7]

Answer:

The surface tension of plain water can cause a needle to float.

Evidently, the addition of detergent to the water reduces the surface tension of the liquid causing the needle to sink.

7 0

2 years ago

A measure of how consistently a result is determined by repeated evaluations is called

Nady [450]

Answer:

The answer is precision.

6 0

3 years ago

Read 2 more answers