1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alla [95]
3 years ago
9

The flywheel of a steam engine runs with a constant angular velocity of 150 rev/min. When steam is shut off, the friction of the

bearings and of the air stops the wheel in 1.6 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 75.0 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 37 cm from the axis of rotation? (d) What is the magnitude of the net linear acceleration of the particle in (c)?
Physics
1 answer:
Annette [7]3 years ago
3 0

Answer:

a) \ddot n = -1.563\,\frac{rev}{min^{2}}, b) \Delta n = 7197.697\,rev, c) a_{t} = 1.009\times 10^{-3}\,\frac{m}{s^{2}}, d) a = 22.823\,\frac{m}{s^{2}}

Explanation:

a) Constant angular acceleration is:

\ddot n = \frac{\dot n - \dot n_{o}}{\Delta t}

\ddot n = \frac{0\,\frac{rev}{min} - 150\,\frac{rev}{min}}{(1.6\,h)\cdot \left(60\,\frac{min}{h} \right)}

\ddot n = -1.563\,\frac{rev}{min^{2}}

b) The amount of revolutions required to stop the flywheel is:

\Delta n = \frac{\dot n^{2}-\dot n_{o}^{2}}{2\cdot \ddot n}

\Delta n = \frac{\left(0\,\frac{rev}{min} \right)^{2}-\left(150\,\frac{rev}{min} \right)^{2}}{2\cdot \left(-1.563\,\frac{rev}{min^{2}} \right)}

\Delta n = 7197.697\,rev

c) The tangential acceleration of the particle is:

a_{t} = \left(1.563\,\frac{rev}{min^{2}} \right)\cdot \left(\frac{1}{3600}\,\frac{min^{2}}{s^{2}}\right)\cdot \left(2\pi\,\frac{rad}{rev}\right)\cdot (0.37\,m)

a_{t} = 1.009\times 10^{-3}\,\frac{m}{s^{2}}

d) The radial acceleration of the particle is:

a_{r} = \left[\left(75\,\frac{rev}{min} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\right]^{2}\cdot (0.37\,m)

a_{r} = 22.823\,\frac{m}{s}

The net linear acceleration is:

a = \sqrt{a_{r}^{2}+a_{t}^{2}}

a = \sqrt{\left(22.823\,\frac{m}{s^{2}} \right)^{2}+\left(1.009\times 10^{-3}\,\frac{m}{s^{2}} \right)^{2}}

a = 22.823\,\frac{m}{s^{2}}

You might be interested in
How much power is needed to move a 2000 kg mass from the bottom of the 150 m talk great pyramid in Egypt up a ramp if the ramp h
docker41 [41]

Answer:

How Heavy? More than 2,300,000 limestone and granite blocks were pushed, pulled, and dragged into place on the Great Pyramid. The average weight of a block is about 2.3 metric tons (2.5 tons).

Explanation:

4 0
2 years ago
Which value is equivalent to 7.2 kilograms?
Elis [28]
B is the right answer glad I could help !!
3 0
3 years ago
The force measuring instrument is called
Phoenix [80]
This instrument is called a spring scale.
5 0
2 years ago
Read 2 more answers
Calculate the net force and the acceleration on the block
Darina [25.2K]

Answer:

Net Force = 10N

Acceleration = 2m/s^2

Explanation:

calculate the net force and the acceleration on the block

Net force on the block F = mass * acceleration

Net force acting in the positive direction = 4N + 6N = 10N

Mass = 5kg

According to newton's second law;

a = F/m

a = 10N/5

a = 2m/s^2

hence the acceleration on the block is 2m/s^2

7 0
3 years ago
If the resultant force acting on a 2.0 kg object is equal to (3.0î + 4.0ĵ) N, what is the change in kinetic energy as the object
12345 [234]

Answer:

ΔK = 24 joules.

Explanation:

ΔK = Work done on the object

Work is equal to the dot product of force supplied and the displacement of the object.

W = F * Δs

Δs can be found by subtracting the vectors (7.0, -8.0) and (11.0, -5.0), which is written as Δs = (11.0 - 7.0, -5.0 - -8.0) which equals (4.0, 3.0).

This gives us

W = < 3, 4 > * < 4, 3 > = (3*4)+(4*3) = 24 J

3 0
1 year ago
Other questions:
  • A 70 kg man is walking at a speed of 2 m/s. What is his Kinetic Energy?
    12·2 answers
  • A friction force of 280 N exists between a cart and the path. If the force of reaction is 766 N, what is the minimum action forc
    7·1 answer
  • . How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?
    15·1 answer
  • When you throw a ball upward, its kinetic energy ____ (DECREASES,INCREASES,REMAINS THE SAME) and its potential energy _____ (DEC
    6·2 answers
  • If Two stars, Betty and Wilma, are both on the main sequence. Betty is more luminous than Wilma. Which one has a hotter surface
    6·1 answer
  • Which term describes energy stored inside the nucleus of an atom?
    10·1 answer
  • A ball is dropped from rest from the top of a building. What force is responsible for the downward motion of the ball?
    13·1 answer
  • What types of cuts do jig saw sanders make?​
    8·2 answers
  • What constant acceleration is required to increase the speed of a car from 26 mi/h to 51 mi/h in 5 seconds
    11·1 answer
  • Imagine that a star-forming cloud collapses but retains all of its mass in a single blob. In order to conserve angular momentum,
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!