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Ilya [14]
3 years ago
8

The model below shows an atom of an element. 9 light grey and 8 dark grey balls sit at the center with 2 concentric black rings

around them. The inner ring has 2 medium grey balls on it, and the outer ring has 6 medium grey balls on it. At bottom, a dark grey ball = +1, a light grey ball = 0, a medium grey ball = negative 1. What is the atomic number of this atom? 6 8 9 16
Chemistry
2 answers:
Elis [28]3 years ago
7 0

Answer: Option (b) is the correct answer.

Explanation:

As it is given that a dark grey ball has +1 charge. This means that it is a proton. And, a light grey ball has has 0 charge. This means it is a neutron.

Whereas a medium grey ball has -1 charge. This means that it is an electron.

As it is known that in a neutral atom the number of protons equal to the number of electrons.

Since, no overall charge is present on the given model of atom. Hence, the atom is neutral in nature.

Also, atomic number is the sum of total number of protons present in an atom. So, in the given atom total number of protons is 8, total number of neutrons is 9, and total number of electrons is also 8.

Thus, we can conclude that the atomic number of given atom is 8.

aleksley [76]3 years ago
3 0

Answer:

sorry if this is a bit late but i know what your talking about and your answer would be 8

stay happy!!

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Answer:

option 3

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8 0
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Answer:

72.8 % (But verify explanation).

Explanation:

Hello,

In this case, with the following obtained results, the percent error is computed as follows:

Volume of vinegar= 7.0 mL

Volume of NaOH= (7+6.6+6.4)/3= 6.7 mL

Used concentration of NaOH= 1.5M

Concentration of acetic acid= (concentration of NaOH*volume of NaOH)/volume of vinegar= (6.7mL*1.5M)/7.0M= 1.44M

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% error in percentage of acetic acid = [(8.64% - 5.0%)/5.0] x 100=72.8 %

Clearly, this result depend on your own measurements, anyway, you can change any value wherever you need it.

Regards.

8 0
2 years ago
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jonny [76]
Where are the choices? without the choices, i think the volcano could increase the earth's temperature
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