Answer:
The molar mass of the unknown gas is 
Explanation:
Let assume that the gas is O2 gas
O2 gas is to effuse through a porous barrier in time t₁ = 4.98 minutes.
Under the same conditions;
the same number of moles of an unknown gas requires time t₂ = 6.34 minutes to effuse through the same barrier.
From Graham's Law of Diffusion;
Graham's Law of Diffusion states that, at a constant temperature and pressure; the rate of diffusion of a gas is inversely proportional to the square root of its density.
i.e

where K = constant
If we compare the rate o diffusion of two gases;

Since the density of a gas d is proportional to its relative molecular mass M. Then;

Rate is the reciprocal of time ; i.e

Thus; replacing the value of R into the above previous equation;we have:

We can equally say:






Answer:
Calcium chloride react with silver nitrate to produce calcium nitrate and silver(I) chloride.
Answer:
a) 24.7 mol
b) 790 g
Explanation:
Step 1: Given data
- Volume of the chamber (V): 200. L
- Room temperature (T): 23 °C
- Pressure of the gas (P): 3.00 atm
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 23°C + 273.15 = 296 K
Step 3: Calculate the moles (n) of oxygen
We will use the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol
Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen
The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.
m = n × M
m = 24.7 mol × 32.00 g/mol = 790 g
Answer:
112.540 gram of N2
Explanation:
From the balanced chemical equation
N2+3H2----->2NH3
It means that 1 mole of Nitrogen needs 3 moles of hydrogen
In term of mass,we can say that
6.048 gram of H2 needs 28.01 gram of N2
or, 1 gram of H2 needs (28.01/6.048) gram of N2
and 24.3gram of H2 needs (24.3*28.01/6.048) gram of N2
=112.540 gram of N2