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Ugo [173]
3 years ago
7

An 1,840 W toaster, a 1,460 W electric frying pan, and a 50 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (T

he three devices are in parallel when plugged into the same socket.) (a) What current (in A) is drawn by each device?
Physics
2 answers:
shutvik [7]3 years ago
7 0

Answer:

Explanation:

Given

Power drawn by toaster P_1=1840\ W

Power drawn by Electric fan P_2=1460\ W

Power drawn by lamp P_3=50\ W

Voltage applied V=120\ V

If appliances are applied in parallel then Voltage applied is same

Power is given by P=\frac{V^2}{R}

Resistance of toaster R_1=\frac{120^2}{1840}=7.82\ \Omega

Resistance of electric Fan R_2=\frac{120^2}{1460}=9.86\ \Omega

Resistance of toaster R_3=\frac{120^2}{50}=288\ \Omega

Current is given by

I=\frac{V}{R}

I_1=\frac{120}{7.82}=15.34\ A

I_2=\frac{120}{9.86}=12.17\ A

I_3=\frac{120}{288}=0.416\ A

Iteru [2.4K]3 years ago
6 0

Answer:

Explanation:

power of toaster, P1 = 1840 W

Power of electric frying pan, P2 = 1460 W

Power of lamp, P3 = 50 W

As they all are connected in parallel, so the voltage is same for all.

Let the current in toaster is i1.

P1 = V x i1

1840 = 120 x i1

i1 = 15.33 A

Let the current in frying pan is i2.

P2 = V x i2

1460 = 120 x i1

i1 = 12.17 A

Let the current in lamp is i3.

P3 = V x i3

50 = 120 x i3

i3 = 0.42 A

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