Question

An 1,840 W toaster, a 1,460 W electric frying pan, and a 50 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (The three devices are in parallel when plugged into the same socket.) (a) What current (in A) is drawn by each device?

Answer 1

Answer:

Explanation:

Given

Power drawn by toaster $P_1=1840\ W$

Power drawn by Electric fan $P_2=1460\ W$

Power drawn by lamp $P_3=50\ W$

Voltage applied $V=120\ V$

If appliances are applied in parallel then Voltage applied is same

Power is given by $P=\frac{V^2}{R}$

Resistance of toaster $R_1=\frac{120^2}{1840}=7.82\ \Omega$

Resistance of electric Fan $R_2=\frac{120^2}{1460}=9.86\ \Omega$

Resistance of toaster $R_3=\frac{120^2}{50}=288\ \Omega$

Current is given by

$I=\frac{V}{R}$

$I_1=\frac{120}{7.82}=15.34\ A$

$I_2=\frac{120}{9.86}=12.17\ A$

$I_3=\frac{120}{288}=0.416\ A$

Answer 2

Answer:

Explanation:

power of toaster, P1 = 1840 W

Power of electric frying pan, P2 = 1460 W

Power of lamp, P3 = 50 W

As they all are connected in parallel, so the voltage is same for all.

Let the current in toaster is i1.

P1 = V x i1

1840 = 120 x i1

i1 = 15.33 A

Let the current in frying pan is i2.

P2 = V x i2

1460 = 120 x i1

i1 = 12.17 A

Let the current in lamp is i3.

P3 = V x i3

50 = 120 x i3

i3 = 0.42 A