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koban [17]
3 years ago
14

8. When a 100 N bag of nails hangs motionless from a single vertical strand of rope, how many newtons of tension are exerted in

the strand? - What if the bag is supported by four vertical strands?
Physics
1 answer:
Svetllana [295]3 years ago
8 0

If the bag is motionless, then it's not accelerating up or down.
That fact right there tells you that the net vertical force on it
is zero.  So the sum of any upward forces on it is exactly equal
to the downward gravitational force ... the bag's "weight".

If the bag is suspended from a single rope, then the tension
in the rope must be equal to the 100-N weight of the bag.

And if there are four ropes holding it up, then the sum of
the four tensions is 100N.  If the ropes have been carefully
adjusted to share the load equally, then the tension is 25N
in each rope.

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What is one piece of evidence that does NOT support the Big Bang Theory?​
svetoff [14.1K]

Answer:

The redshift data does not support the Big Bang Theory and  without the redshift interpretation favored by the Big bang, there is  no Big Bang.  

Edwin Hubble did not believe that the redshift indicated  expansion. Hubble saw the redshift as an hitherto unrecognized  principle of nature.  The redshift is the effect of centripetal force mv2/r = mv2/ct =  v/c(mv/t) = v/c(p/t)= (v/c)m

The unrecognized principle of nature is the refraction effect of  gravity on light.  

n=c/v or v= c/n.

The Universe is older than 13.7 Billion years, likely around  16.5 billion years.  

The proper law of Gravity is W = -mGM/r + cmV = -mu/r + cP where  cP is the so-called "Dark Energy", or the actual vector Momentum  Energy cmV= cP. This is The Quaternion Universe with scalar and  vector energy!

Hope this helps!

3 0
3 years ago
You have a rock sample and analyze it for the presence of radioactive isotopes in order to determine when it was formed. You fin
Firdavs [7]

Answer:

the decay of half of the nuclei only a half-life has passed ,  b) in rock time it is 1 108 years

Explanation:

The radioactive decay is given by

         N = N₀ e^{\lambda t}

If half of the atoms have decayed

       ½ N₀ = N₀ e^{\lambda t}

       ½ = e^{\lambda t} ₀

       Ln 0.5 = - λ t

       t = - ln 0.5 /λ

The definition of average life time is

      T_{1/2}= ln 2 / λ

       λ = ln 2 /  T_{1/2}

       λ = 0.693 / 100 10⁶

       λ = 0.693 10⁻⁸ years

We replace

       t = -ln 0.5 / 0.693 10⁻⁸

       t = 10⁸ years

We see that for the decay of half of the nuclei only a half-life has passed

b) in rock time it is 1 108 years

8 0
3 years ago
In a model of the solar system that was about as large as a college campus how large would the Sun be?
nordsb [41]
Small car is the answer
8 0
3 years ago
What is a smash shot?<br> (BADMINTON)
zaharov [31]
The smash shot in badminton is considered one of the most powerful kind of shot that can tilt the score in your favour. This shot can only be excited when the shuttle is high in the air. The reason behind that is because from a high elevation point, the shuttle is smashed downward over the net into the opponent's court. There is almost no defence against such a shot because it is slammed so quickly and is at such a downward angle that it is difficult for the opponent to receive it.
5 0
3 years ago
A long string is wrapped around a 6.6-cm-diameter cylinder, initially at rest, that is free to rotate on an axle. The string is
lys-0071 [83]

Answer:

\omega_f=571.42\ rpm

Explanation:

It is given that,

Diameter of cylinder, d = 6.6 cm

Radius of cylinder, r = 3.3 cm = 0.033 m

Acceleration of the string, a=1.5\ m/s^2

Displacement, d = 1.3 m

The angular acceleration is given by :

\alpha =\dfrac{a}{r}

\alpha =\dfrac{1.5}{0.033}

\alpha =45.46\ rad/s^2

The angular displacement is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{1.3}{0.033}

\theta=39.39\ rad

Using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

Here, \omega_i=0

\omega_f=\sqrt{2\alpha \theta}

\omega_f=\sqrt{2\times 45.46\times 39.39}

\omega_f=59.84\ rad/s

Since, 1 rad/s = 9.54 rpm

So,

\omega_f=571.42\ rpm

So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.

5 0
4 years ago
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