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exis [7]
2 years ago
8

The magnetic field strength within a long solenoid isb=4.0t t, where t is time in seconds. if the radius of thesolenoid is1.0 cm

, what is the magnitude of the non-coulomb force that acts on a6.0 c charge a distance6.0 cmfrom the axis of the solenoid?
Physics
1 answer:
densk [106]2 years ago
3 0
The current problem can solved by using Faraday's law of induction which is actually one of the Maxwell's equations. It is stated as follows:
F=qE

Where
F = Non-coulomb force
q = 6.0 C
E = (dB/dt)*r^2*(2/R); In which dB/dt = 4 T; r = 1 cm = 0.01 m, R = 6.0 cm = 0.06 m, E = Newtons/Coulob
Substituting;

E = 4*0.01^2*(2/0.06) = 1/75

Therefore,
F = qE = 6*1/75 = 0.08 N
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How does Newton's third law of motion give a property of process​
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2 years ago
in a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallw
madam [21]

Answer:

μ=0.151

Explanation:

Given that

m= 3.5 Kg

d= 0.96 m

F= 22 N

v= 1.36 m/s

Lets take coefficient of kinetic friction = μ

Friction force Fr=μ m g

Lets take acceleration of block is a m/s²

F- Fr = m a

22 -  μ x 3.5 x 10 = 3.5 a         ( take g =10 m/s²)

a= 6.28 - 35μ  m/s²

The final speed of the block is v

v= 1.36 m/s

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v²= u²+ 2 a d

u= 0 m/s given that

1.36² = 2 x a x 0.96

a= 0.963 m/s²

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3 0
3 years ago
When applying a horizontal force of 30N, an object of mass 6 kg accelerates at 4m/s2. The force of friction on the surface must
Rus_ich [418]
Using Newton's Second Law, F = ma, where F is the net force

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30N-24N = 6N

F_{f} = 6N
4 0
2 years ago
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