Question

The magnetic field strength within a long solenoid isb=4.0t t, where t is time in seconds. if the radius of thesolenoid is1.0 cm, what is the magnitude of the non-coulomb force that acts on a6.0 c charge a distance6.0 cmfrom the axis of the solenoid?

Answer 1

The current problem can solved by using Faraday's law of induction which is actually one of the Maxwell's equations. It is stated as follows:
F=qE

Where
F = Non-coulomb force
q = 6.0 C
E = (dB/dt)*r^2*(2/R); In which dB/dt = 4 T; r = 1 cm = 0.01 m, R = 6.0 cm = 0.06 m, E = Newtons/Coulob
Substituting;

E = 4*0.01^2*(2/0.06) = 1/75

Therefore,
F = qE = 6*1/75 = 0.08 N