Answer:
the resulting angular acceleration is 15.65 rad/s²
Explanation:
Given the data in the question;
force generated in the patellar tendon F = 400 N
patellar tendon attaches to the tibia at a 20° angle 3 cm( 0.03 m ) from the axis of rotation at the knee.
so Torque produced by the knee will be;
T = F × d⊥
T = 400 N × 0.03 m × sin( 20° )
T = 400 N × 0.03 m × 0.342
T = 4.104 N.m
Now, we determine the moment of inertia of the knee
I = mk²
given that; the lower leg and foot have a combined mass of 4.2kg and a given radius of gyration of 25 cm ( 0.25 m )
we substitute
I = 4.2 kg × ( 0.25 m )²
I = 4.2 kg × 0.0626 m²
I = 0.2625 kg.m²
So from the relation of Moment of inertia, Torque and angular acceleration;
T = I∝
we make angular acceleration ∝, subject of the formula
∝ = T / I
we substitute
∝ = 4.104 / 0.2625
∝ = 15.65 rad/s²
Therefore, the resulting angular acceleration is 15.65 rad/s²
Answer:
Atoms of tellurium (Te) have the greatest average number of neutrons equal to 76.
Explanation:
In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.
To calculate the number of neutrons we can take the difference of Atomic number and mass number:
Number of neutrons = mass number - atomic number
<u>- Tin:</u>
Atomic number = 50
Mass number = 119
Number of neutrons = mass number - atomic number = 119 - 50
Number of neutrons = 69
<u>- Antimony(Sb):</u>
Atomic number = 51
Mass number = 122
Number of neutrons = mass number - atomic number = 122 - 51
Number of neutrons = 71
<u>- Tellurium(Te):</u>
Atomic number = 52
Mass number = 128
Number of neutrons = mass number - atomic number = 128 - 52
Number of neutrons = <u>76</u>
<u>- Iodine(I):</u>
Atomic number = 53
Mass number = 127
Number of neutrons = mass number - atomic number = 127 - 53
Number of neutrons = 74
Here, the greatest number of neutrons is for the atoms of Tellurium(Te).
Answer with Explanation:
We are given that mass of block=0.0600 kg
Initial speed of block=0.63 m/s
Distance of block from the hole when the block is revolved=0.47 m
Final speed=3.29 m/s
Distance of block from the hole when the block is revolved=
a.We have to find the tension in the cord in the original situation when the block has speed =
Because tension is equal to centripetal force
Substitute the values
b.
c.Work don=Final K.E-Initial K.E
