I believe it means the imitations on what you did what were you not able to do to the object. I'm not too sure but I believe that's what it means. I hope I was able to help
Answer:
- <em>The pH of the solution is </em><u><em>7</em></u>
Explanation:
<em>The pH</em> is a measure of the acidity of the solutions. It is defined as the negative logarithm of the molar concentration of hydrogen ions (H⁺).
<em>The hydrogen ion concentration of this solution is 1 × 10⁻⁷ M.</em>
Hence:
- pH = - log (1 × 10⁻⁷) = - (-7) = 7
This pH corresponds to a neutral solution (neither acid nor alkaline).
You should remember this relation bwtween pH and acidity/alkaliinity:
- Low pH (0.0 or close) corresponds to strong acids
- HIgh pH (14.0 or close) corresponds to strong bases
- Acids have pH between 0.0 and 7.0
- Bases have pH between 7.0 and 14.0
Answer:
The reaction is not at equilibrium and reaction must run in forward direction.
Explanation:
At the given interval, concentration of NO = 
Concentration of 
= 
Concentration of NOBr = 
Reaction quotient,
, for this reaction = ![\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNOBr%5D%5E%7B2%7D%7D%7B%5BNO%5D%5E%7B2%7D%5BBr_%7B2%7D%5D%7D)
species inside third bracket represents concentrations at the given interval.
So, 
So, the reaction is not at equilibrium.
As 
therefore reaction must run in forward direction to increase and make it equal to 
.
I think it can be dissolved but if u keep adding more sugar it will stop dissolving
Missing question: What is the rate constant for the reaction?
<span>[RS2](mol L-1) Rate (mol/(L·s))
0.150 0.0394
0.250 0.109
0.350 0.214
0.500 0.438</span>
Chemical reaction: 3RS₂ → 3R + 6S.
Compare second and fourth experiment, when concentration is doubled, rate of concentration is increaced by four. So rate is:
rate = k·[RS₂]².
k = 0,438 ÷ (0,500)².
k = 1,75 L/mol·s.
