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madam [21]
3 years ago
10

Alternating Current In Europe, the voltage of the alternating current coming through an electrical outlet can be modeled by the

function V 230 sin (100t), where tis measured in seconds and Vin volts.What is the frequency of the voltage
Physics
1 answer:
stealth61 [152]3 years ago
7 0

Answer:

\frac{50}{\pi }Hz

Explanation:

In alternating current (AC) circuits, voltage (V) oscillates in a sine wave pattern and has a general equation as a function of time (t) as follows;

V(t) = V sin (ωt + Ф)            -----------------(i)

Where;

V = amplitude value of the voltage

ω = angular frequency = 2 π f        [f = cyclic frequency or simply, frequency]

Ф = phase difference between voltage and current.

<u><em>Now,</em></u>

From the question,

V(t) = 230 sin (100t)              ---------------(ii)

<em><u>By comparing equations (i) and (ii) the following holds;</u></em>

V = 230

ω = 100

Ф = 0

<em><u>But;</u></em>

ω = 2 π f = 100

2 π f = 100             [divide both sides by 2]

π f = 50

f = \frac{50}{\pi }Hz

Therefore, the frequency of the voltage is \frac{50}{\pi }Hz

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Two train whistles have identical frequencies of 1.85 102 Hz. When one train is at rest in the station and the other is moving n
Makovka662 [10]

Answer:

Explanation:

frequency of whistle = 1.85 x 10² = 185 Hz

frequency of beat heard = 8 beat /s . No of beat produced is equal to difference of frequencies of two sound source . Here difference is created due to Doppler effect . One of the train is moving so it will have apparent frequency which is different one from its original frequency .

When the moving train is approaching the observer , its frequency will be higher . As beat is heard at the rate of 8 beats / s , apparent frequency of approaching train will be 185 + 8 = 193 Hz .

Applying Doppler's formula of apparent frequency ,

193 = 185 x V / ( V - v ) , where V is velocity of sound and v is velocity of train .

193 V - 193 v = 185 V

193 v = 8 V

v = 8 x V / 193

= 8 x 343 / 193

= 14.21 m /s

Second possibility is that apparent velocity is less ie 185 - 8 = 177 Hz

In that case moving train will be moving away from observer . If its velocity be v

177 = 185 x V / ( V + v )

177 V + 177 v = 185 V

v = 8 x 343 / 177

= 15.50 m /s .

6 0
4 years ago
A rod attracts a positively charged hanging ball. the rod is?a) negativeb) positivec) neutrald) either negative or neutrale) eit
makvit [3.9K]

Answer:

The correct option is a

Explanation:

This question seeks to test a general rule in physics (on charges) which states that <u>like charges repel but unlike charges attract</u>. This means that, a negatively charged substance will repel or not attract another negatively charged material and the same applies to a positively charged substance also. However, a <u>negatively charged substance will attract a positively charged material and vice versa,</u> hence only a negatively charged rod will attract a positively charged hanging ball.

8 0
4 years ago
it takes you 9.5 min to walk with an average velocity of 1.2m/s to the north from the bus stop to the museum entrance. what is y
MAVERICK [17]

Answer:

x=684m

Explanation:

v=velocity

x=displacement

t=time

equation: v=x/t

v=1.2m/s

x=?

t=9.5min=570s

1.2=x/570

570*1.2=x/570*570

x=684m

3 0
3 years ago
Which rational number could be graphed between 0 and 1?A number line going from negative 5 to positive 3 in increments of 1.Nega
vovikov84 [41]

In order to find which rational number is between 0 and 1, let's convert them into their decimal form:

\begin{gathered} \text{negative one-half:} \\ -\frac{1}{2}=-0.5 \\  \\ \text{one}-\text{fourth:} \\ \frac{1}{4}=0.25 \\  \\ \text{three}-\text{halves:} \\ 3\cdot\frac{1}{2}=\frac{3}{2}=1.5 \\  \\ 1.75 \end{gathered}

Looking at the numbers in their decimal form, we can see that the number between 0 and 1 is one-fourth, therefore the correct option is the second one.

7 0
1 year ago
Calculate the pressure exerted on the floor when an
skad [1K]

P = F / A

P = 2400 / 4

P = 24 × 100 / 4

P = 6 × 100

P = 600 N/m^2

7 0
3 years ago
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