Answer:
Explanation:
The momentum of an object is given by 
.
Plugging in values, we have:
.
Answer:
2.6 m/s
Explanation:
mass of Jerome (Mj) = 102 kg
mass of Micheal (Mm) = 98 kg
mass of each cart (Mc) = 14 kg
recoil speed of Jerone and Micheal after push (Vi) = ?
mass of Suzie (Ms) = 44 kg
Suzie's speed after push (Vs) = 9.6 m/s
From the conservation of momentum, initial momentum = final momentum
Since they all are initially at rest the initial momentum is 0 and hence the final momentum is also 0.
Therefore for the final momentum we have
(Mj + Mm + Mc) Vi - (Ms + Mc) Vs = 0 ( the negative sign is because they move in opposite directions)
((102 + 98 + 14) x Vi ) - ((44 + 14) x 9.6) = 0
(214 x Vi) - (58 x 9.6) = 0
214 Vi = 556.8
Vi = 556.8 / 214 = 2.6 m/s
Answer:
V2 = 37.5 L
Explanation:
Given the following data;
Initial volume, V1 = 25 L
Initial temperature, T1 = 20°C
Final temperature,T2 = 30°C
To find the final volume V2, we would use Charles' law;
Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.
Mathematically, Charles is given by;
Making V2 as the subject formula, we have;
V2 = 37.5 L
Answer:
T = 74.8 N
Explanation:
Given:
- The angle with the horizontal θ = 36°
- The tension in the strap T
- The amount of work done W = 908 J
- The distance travelled by the suitcase s = 15 m
Find:
what is the tension in the strap?
Solution:
- From definition we have that the work-done by a force F is given by the dot product of the force vector and the displacement vector as expressed below:
W = F.s
- The scalar form of the work done includes the component of force F along the direction of displacement as follows:
W = F*s*cos(θ)
- Now we can calculate the Tension force T from the given data as follows:
W = T*s*cos(θ)
T = W / (s*cos(θ))
T = 908 / (15*cos(36))
T = 74.8 N
Answer:
The total resistance is 5000 N. So the net force left for acceleration is 7 000 N (12 000 - 5 000).
7000 N applied to 2x700 kg gives a maximum acceleration of
a = F/m = 7000/1400kg = 5 m/s^2
At 5m/s^2, it will take 8 s to reach 40 m/s. In 8 second the distance covered will be
d = 1/2 at^2 = 1/2 x 5 x 8^2 = 160 m
Because each glider has the same drag and inertia, the tension in the rope between the gliders will be exactly half of the tension between plane and the two gliders:
12 000/2 = 6 000N.
