Mass = 0.201kg
Energy = 15J
temperature change = 10C
Energy(E) = mass(m) × specific heat capacity(c) × temperature change(θ)
we can rearrange this to make specific heat capacity the subject
c =
![\frac{E}{m\theta}](https://tex.z-dn.net/?f=%20%5Cfrac%7BE%7D%7Bm%5Ctheta%7D%20)
c =
![\frac{15}{2.01}](https://tex.z-dn.net/?f=%20%5Cfrac%7B15%7D%7B2.01%7D%20)
c =7.46268657
Explanation:
This should be of help:
An atom is made up of three subatomic particles:
- Protons are the positively charged particles.
- Electrons are the negatively charged particles.
- Neutrons do not carry any charges.
A neutral atom is an atom that has not lost or gained any amount of electrons.
In a neutral atom;
the number of protons and electrons are the same
Usually atoms are designated this way:
ᵃₙX
where X is the symbol of the atom
a is the mass number of the atom
n is the atomic number of the atom
The mass number = number of protons + number of neutrons
Atomic number = number of protons
Note; atomic number is the same as the number protons and the number of electrons in a neutral atom.
Use this guide to solve the problem
Learn more:
Atomic number brainly.com/question/5425825
#learnwithBrainly
Answer:
a. 2143 turns/m
b. 111.5 m
Explanation:
a. The minimum number of turns per unit length (N/L) can be found using the following equation:
![B = \frac{\mu_{0}NI}{L}](https://tex.z-dn.net/?f=%20B%20%3D%20%5Cfrac%7B%5Cmu_%7B0%7DNI%7D%7BL%7D%20)
![\frac{N}{L} = \frac{B}{\mu_{0}I} = \frac{3.50 \cdot 10^{-2} T}{4\pi \cdot 10^{-7} Tm/A*13.0 A} = 2143 turns/m](https://tex.z-dn.net/?f=%20%5Cfrac%7BN%7D%7BL%7D%20%3D%20%5Cfrac%7BB%7D%7B%5Cmu_%7B0%7DI%7D%20%3D%20%5Cfrac%7B3.50%20%5Ccdot%2010%5E%7B-2%7D%20T%7D%7B4%5Cpi%20%5Ccdot%2010%5E%7B-7%7D%20Tm%2FA%2A13.0%20A%7D%20%3D%202143%20turns%2Fm%20)
Hence, the minimum number of turns per unit length is 2143 turns/m.
b. The total length of wire is the following:
![N = 2143 turns/m*L = 2143 turns/m*46.0 \cdot 10^{-2} m = 986 turns](https://tex.z-dn.net/?f=%20N%20%3D%202143%20turns%2Fm%2AL%20%3D%202143%20turns%2Fm%2A46.0%20%5Ccdot%2010%5E%7B-2%7D%20m%20%3D%20986%20turns%20)
Since each turn has length 2πr of wire, the total length is:
![L_{T} = N*2\pi r = 986 turn*2*\pi*1.80 \cdot 10^{-2} m = 111.5 m](https://tex.z-dn.net/?f=%20L_%7BT%7D%20%3D%20N%2A2%5Cpi%20r%20%3D%20986%20turn%2A2%2A%5Cpi%2A1.80%20%5Ccdot%2010%5E%7B-2%7D%20m%20%3D%20111.5%20m%20)
Therefore, the total length of wire required is 111.5 m.
I hope it helps you!
The light must be either very dim or else non-existent.
We can't see the light wave or the label.
The total work done by the electric field on the charge is given by the scalar product between the electric force acting on the charge and the displacement of the charge:
![W=F d cos \theta](https://tex.z-dn.net/?f=W%3DF%20d%20cos%20%5Ctheta)
where the force is F=qE, d=0.556 and
![\theta=55.2^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D55.2%5E%7B%5Ccirc%7D)
. Using the value of q and E given by the problem, we find