First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
An increase in motion and less attraction between particles
Explanation:
To solve this problem, follow these steps;
- Obtain a balanced equation of the reaction and familiarize with the reactants and products.
- Find the number of moles of the reacting species since they are the known matter in terms of quantity.
- From the number of moles, determine the limiting reactant.
- The limiting reactant is the one given in short supply.
- Such reactant determines the extent of the reaction.
- Compare the moles of this specie to that of the products using the balanced equation.
- Obtain the mole of the desired product and find the mass or desired quantity.
- simply work from the known specie to the unknown
learn more:
Number of moles brainly.com/question/13064292
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<span> Greenhouse gases were not historically present in the atmosphere.</span>
Be= Beryllium= weight 9.01
Cl= Chlorine= weight 35.45
Since there are 2 Chlorine, you have to add Chlorine twice.
9.01 + 35.45 + 35.45= 79.91
Answer: 79.91
(This answer does not include sig.figs)
