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2 years ago

14

What is one advantage of reflecting telescopes? a they have two focal points. b they focus all colors perfectly. c they touch up

images. d they use smaller mirrors?

1 answer:

artcher [175]2 years ago

5 0

If I'm not mistaken it's b

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The general kinematic equations of motion for vertical displacement can also be simplified significantly. Write the simplified

Setler [38]

Answer:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

Explanation:

The general kinematic equation for horizontal displacement is gives as:

Δx = v₀t + (1/2)at²

Where

Δx = change in the x direction

v₀ = initial velocity

t = time

a = acceleration

If the body is vertically instead of horizontally, Δx is changed to Δy

Δy = v₀t + (1/2)at²

For a vertical moving body, the acceleration it experiences is the gravitational accerelation of the earth 'g'

So the equation becomes:

Δy = v₀t + (1/2)gt²

where g = 9.81 m/s if the body is moving downwards and g = -9.81 m/s if the body is moving upwards

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3 years ago

This is science :)

iris [78.8K]

1 to 5 would be your answer

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2 years ago

What is the period of a 1.4-m pendulum?

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Answer:(A)

Explanation: ...

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2 years ago

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It is the first on differences in water temperature.
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3 years ago

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A 6.2 kg ladder, 1.97 m long, rests on two sawhorses. Sawhorse A is 0.64 m from one end of the ladder, and sawhorse B is 0.17 m

Keith_Richards [23]

Answer:

42.69 N and 18.07 N

Explanation:

We are given that

Mass of ladder=6.2 kg

Length of ladder=1.97 m

Distance of Sawhorse A from one end=0.64 m

Distance of sawhorse B from other end=0.17 m

Let center of Ladder= $\frac{1.97}{2}=0.985 m$

Now, the distance of sawhorse A from center=r=0.985-0.64=0.345 m

Distance of sawhorse B from center of ladder=0.985-0.17=0.815 m

Force one ladder due to gravity=mg= $6.2\times 9.8=60.76N$

Where $g=9.8 m/s^2$

Torque applied on Sawhorse A= $0.345F_a$

Torque applied on Sawhorse B= $0.815F_b$

In equilibrium

$0.345F_a=0.815F_b$

$F_b=\frac{0.345}{0.815}F_a$

Total force= $F_a+F_b$

$F_a+\frac{0.345}{0.815}F_a=60.76$

$\frac{0.815F_a+0.345F_a}{0.815}=60.76$

$\frac{1.16}{0.815}F_a=60.76$

$F_a=\frac{60.76\times 0.815}{1.16}=42.69 N$

$F_b=\frac{0.345}{0.815}\times 42.69=18.07 N$

8 0

3 years ago