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I am Lyosha [343]
3 years ago
8

RATIO of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is:

Physics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

<h2>3) \:  \:  \frac{5}{27}</h2>

Explanation:

Hope it is helpful....

adell [148]3 years ago
5 0

Answer:

5/27

Explanation:

wavelengths for Lyman series

\lambda=\frac{1}{R(1-\frac{1}{4} })=\frac{4}{3R}

wavelengths for Balmer series

\lambda_B=\frac{1}{R(\frac{1}{4}-\frac{1}{9})  } =\frac{1}{R(\frac{5}{36}) } =\frac{36}{5R}

\frac{ \lambda_L}{ \lambda_B} =\frac{4}{3R} \times\frac{5R}{36} =5/27

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<u>OAmalOHopeO</u>

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In April 1974, Steve Prefontaine completed a 10.0 km race in a time of 27 min , 43.6 s . Suppose "Pre" was at the 7.43 km mark a
Novay_Z [31]

Answer:

Acceleration, a = 0.101 m/s²

Explanation:

Average speed = total distance / total time.

At the 7.43km mark, total distance = 7.43km or 7430m

Total time = 25 * 60 s = 1500s

Average speed = 7430m/1500s = 4.95m/s

He then covers (10 - 7.43)km = 2.57 km = 2570 m

in t = 27m43.6s - 25min = 2m43.6s = 163.6 s

Then he accelerates for 60 s, and maintains this velocity V, for the remaining (163.6 - 60)s = 103.6 s.

From V = u + at; V = 4.95m/s + a *60s

Distance covered while accelerating is

s = ut + ½at² = 4.95m/s * 60s + ½ a *(60s)² = 297m + a*1800s²

Distance covered while at constant velocity, v after accelerating is

D = velocity * time

Where v = 4.95m/s + a*60s

D = (4.95m/s + a*60s) * 103.6s = 512.82m + a*6216s²

Total distance covered after initial 7.43 km, S + D = 2570 m, so

2570 m = 297m + a*1800s² + 512.82m + a*6216s²

2570 = 809.82 + a*8016

a = 809.82m / 8016s² = 0.101 m/s²

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3 years ago
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larisa [96]

Answer:

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Explanation:

5 0
3 years ago
A piece of wire length 30cm and cross sectional area of 0.5mm^2 has a resistance of 5ohms at 20°c. It is then heated to a temper
Grace [21]

Answer:

8.333*10^-6 ohms

Explanation:

Resistivity of a material is expressed as;

p = RA/l

R is the resistance of the material

A is the cross sectional area

l is the length of the material

Given

R = 5 ohms

A = 0.5mm^2

A = 5 * 10^-7m^2

l = 30cm  = 0.3m

Substitute into the formula;

p = (5 *  5 * 10^-7m^2)/0.3

p = 25 * 10^-7/0.3

p = 0.0000025/0.3

p = 8.333*10^-6

Hence its resistivity at 20 degrees Celsius is 8.333*10^-6 ohms

7 0
3 years ago
What is the force measured in Newtons between a proton and an electron in the ground state?
goldenfox [79]
The answer is zero hope I helped
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3 years ago
A man supports himself and the uniform horizontal beam pulling the rope with a force T.The weights of men and the beam are 883 N
artcher [175]

Answer:

T=502.5N

Ax=171.8N

Explanation:

The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:

vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0

Now  

horizontal forces sum = Ax - Tcos70

Now Moment about B

-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0

Ay=453.6N

Now substitute in sum of vertical forces T=502.5N

Ax=171.8N

3 0
3 years ago
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