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I am Lyosha [343]
2 years ago
8

RATIO of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is:

Physics
2 answers:
katen-ka-za [31]2 years ago
8 0

Answer:

<h2>3) \:  \:  \frac{5}{27}</h2>

Explanation:

Hope it is helpful....

adell [148]2 years ago
5 0

Answer:

5/27

Explanation:

wavelengths for Lyman series

\lambda=\frac{1}{R(1-\frac{1}{4} })=\frac{4}{3R}

wavelengths for Balmer series

\lambda_B=\frac{1}{R(\frac{1}{4}-\frac{1}{9})  } =\frac{1}{R(\frac{5}{36}) } =\frac{36}{5R}

\frac{ \lambda_L}{ \lambda_B} =\frac{4}{3R} \times\frac{5R}{36} =5/27

<u />

<u>OAmalOHopeO</u>

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If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

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Explanation:

From the question we are told that

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