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I am Lyosha [343]
3 years ago
8

RATIO of longest wavelengths corresponding to Lyman and Balmer series in hydrogen spectrum is:

Physics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

<h2>3) \:  \:  \frac{5}{27}</h2>

Explanation:

Hope it is helpful....

adell [148]3 years ago
5 0

Answer:

5/27

Explanation:

wavelengths for Lyman series

\lambda=\frac{1}{R(1-\frac{1}{4} })=\frac{4}{3R}

wavelengths for Balmer series

\lambda_B=\frac{1}{R(\frac{1}{4}-\frac{1}{9})  } =\frac{1}{R(\frac{5}{36}) } =\frac{36}{5R}

\frac{ \lambda_L}{ \lambda_B} =\frac{4}{3R} \times\frac{5R}{36} =5/27

<u />

<u>OAmalOHopeO</u>

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7 0
3 years ago
Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of
xxMikexx [17]

Answer:

Frequency of the light will be equal to 6.97\times 10^{1}Hz

Explanation:

We have given wavelength of the light \lambda =430nm=430\times 10^{-9}m

Velocity of light is equal to v=3\times 10^8m/sec

We have to find the frequency of light

We know that velocity is equal to v=\lambda f, here \lambda is wavelength and f is frequency of light

So frequency of light will be equal to f=\frac{v}{\lambda }=\frac{3\times 10^8}{430\times 10^{-9}}=6.97\times 10^{1}Hz

So frequency of the light will be equal to 6.97\times 10^{1}Hz

5 0
3 years ago
Light bulb is connected to a 110-V source. What is the resistance of this bulb if it is a 100-W bulb
masya89 [10]

Answer:

<h2>121ohms</h2>

Explanation:

Formula used for calculating power P = current * voltage

P = IV

From ohms law, V = IR where R is the resistance. Substituting V = IR into the formula for calculating power, we will have;

P = IV

P =(V/R)V

P = V²/R

Given parameters

Power rating of the bulb P = 100 Watts

Source voltage V = 110V

Required

Resistance of the bulb R

Substituting the given parameters into the formula for calculating power to get Resistance R;

P = V²/R

100 = 110²/R

R = 110²/100

R = 110 * 110/100

R = 12100/100

R = 121 ohms

<em>Hence, the resistance of this bulb is 121 ohms</em>

5 0
3 years ago
En el País Vasco los deportistas rurales levantan enormes piedras hasta su hombro. En un concurso , Jose levanta una piedra de 2
Mama L [17]

Answer:

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

Explanation:

The sportsman that lifts the stone with a greater mass needs a higher force (El deportista que levanta la piedra con mayor masa necesita una mayor fuerza):

José

F = (200\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 1961.4\,N

Txomin

F = (220\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

F = 2157.54\,N

Txomin lifted the stone with greater mass. (Txomin levantó la roca con mayor fuerza).

5 0
3 years ago
The Moon's center is 3.9x10 m from Earth's center. The Moon is 1.5x10^8 km from the Sun's center. If the mass of the Moon is 7.3
nika2105 [10]

Explanation:

It is given that The Moon's center is 3.9x10⁸ m from Earth's center. The moon 1.5x10⁸ km from the Sun's center. We need to find the ratio of the gravitational forces exerted by Earth and the Sun on the Moon.

The gravitational force is given by :

F=\dfrac{Gm_em_m}{r^2}

It means F\propto \dfrac{1}{r^2}

So,

\dfrac{F_1}{F_2}=\dfrac{r_2}{r_1}

r₁ = 3.9x10⁸ km

r₂= 1.5x10⁸ km

So,

\dfrac{F_1}{F_2}=\dfrac{1.5\times 10^8}{3.9\times 10^8}\\\\\dfrac{F_1}{F_2}=\dfrac{5}{13}

Hence, the ratio of the gravitational forces exerted by Earth and the Sun on the Moon is 5:13.

3 0
3 years ago
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