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Gre4nikov [31]
3 years ago
6

A recipe for fruit calls for 2 cans of pineapple juice and 3 cans of orange juice. Hiri is making a large batch for a community

function and uses 72 cans of orange juice. How many cans of pineapple juice should he use?
Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

48  cans of pineapple juice he should use.

Step-by-step explanation:

This, is a problem of ratio where we have to use the concept

a:b = c:d which can be also written as

a/b = c/d

______________________________________________________

According recipe

we find ratio of pineapple and orange juice

amount pine apple juice :  amount of orange juice = 2 cans : 3 cans

Thus, ratio of pineapple and orange juice = 2:3

___________________________________

Given that this recipe is used for making juice in large batch for a community function

Given

amount of orange juice = 72 cans

let the amount of  pine apple juice be x

ratio of pineapple and orange juice in this case

amount pine apple juice :  amount of orange juice = x cans : 72 cans

ratio of pineapple and orange juice in this case= x : 72

since recipe used is same.

ratio will be same in both case that in recipe ratio and large batch preparation for community function

Thus,

x:72 = 2:3

which can also be written as

x/ 72 = 2/3

x = 2/3 * 72 = 48

Thus, 48  cans of pineapple juice he should use.

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A pew research Center project on the state of news media showed that the clearest pattern of news audience growth in 2012 came o
KengaRu [80]

Answer:

Step-by-step explanation:

Given that:

the sample proportion p = 0.39

sample size = 100

Then np = 39

Using normal approximation

The sampling distribution from the sample proportion is approximately normal.

Thus, mean \mu _{\hat p} = p = 0.39

The standard deviation;

\sigma = \sqrt{\dfrac{p(1-p)}{n} }

\sigma = \sqrt{\dfrac{0.39(1-0.39)}{100} }

\sigma = 0.048

The test statistics can be computed as:

Z = \dfrac{{\hat _{p}} - \mu_{_ {\hat p}} }{\sigma_{\hat p}}

Z = \dfrac{0.3 - 0.39 }{0.0488}

Z = -1. 8 4

From the z - tables;

P (\hat p \le 0.3 ) = P(z \le -1.84)

\mathbf{P (\hat p \le 0.3 ) = 0.0329}

(b)

Here;

the sample proportion = 0.39

the sample size n = 400

Since np = 400 * 0.39 = 156

Thus, using normal approximation.

From the sample proportion, the sampling distribution is approximate to the mean \mu_{\hat p} =  p = 0.39

the standard deviation \sigma_{\hat p} = \sqrt{\dfrac{p(1-p)}{n} }

\sigma_{\hat p} = \sqrt{\dfrac{0.39 (1-0.39)}{400} }

\sigma_{\hat p} =0.0244

The test statistics can be computed as:

Z = \dfrac{{\hat _{p}} - \mu_{_ {\hat p}} }{\sigma_{\hat p}}

Z = \dfrac{0.3 - 0.39 }{0.0244}

Z = -3.69

From the z - tables;

P (\hat p \le 0.3 ) = P(z \le -3.69)

\mathbf{P (\hat p \le 0.3 ) = 0.0001}

(c) The effect of the sample size on the sampling distribution is that:

As sample size builds up, the standard deviation of the sampling distribution decreases.

In addition to that, reduction in the standard deviation resulted in increases in the Z score, and the probability of having a sample proportion  that is less than 30% also decreases.

6 0
3 years ago
Jaun rides the bus to school each day he always arrives at his bus stop on time but his bus is late 80% of the time
Yuri [45]

The correct probability that Juan's bus is going to be late every week next week is 20 percent.

<h3>How to solve for the probability</h3>

We have the total number in the stimulation on to be from 0 to 9

On the fact that it would be late, the number ranges from 2 to 9

Hence the fact that it would be late would be

2/10

= 0.2

0.2 is also the same as 20 percent.

<h3>Complete question</h3>

Juan rides the bus to school each day. He always arrives at his bus stop on time, but his bus is late 80% of the time. Juan runs a simulation to model this using a random number generator. He assigns these digits to the possible outcomes for each day of the week:

• Let 0 and 1 = bus is on time

• Let 2, 3, 4, 5, 6, 7, 8, and 9 = bus is late

The table shows the results of the simulation.

Read more on simulation here:

brainly.com/question/24912812

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8 0
2 years ago
-2x+6=30-6x. -6,6,-8,8
Illusion [34]
-2x + 6 = 30 - 6x
--> -2x + 6x = 30 - 6
<span>--> 4x = 24
</span><span>--> x = 24/4
</span><span>--> x = 6</span>
4 0
3 years ago
A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin
riadik2000 [5.3K]

Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

P(Z>1.1547)=1-0.8789

P(Z>1.1547)=0.1241

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

7 0
3 years ago
1,200 tv; 10% discount
klio [65]
Since you get 10% off, you only pay 90% of the price.
1200 x 0.90 = 1080

Therefore the price is $1080 before taxes.
5 0
3 years ago
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