Real word problems that have more than one answer can be described by relations?

The distribution of the amount of money spent by students on textbooks in a semester is approximately normal in shape with a mea

Archy [21]

Answer:

Step-by-step explanation:

Given data:

$\mu = 473$

standard deviation is $\sigma= 28$

As distribution is normal in shape and values are symmetrical

The standard deviation rule says that 95% of observation lies between the second standard deviation of the mean

so, approximately only 5% of observation lies outside the interval and normal shape is symmetric. hence approximately 0.15% of observation lies above the interval

$= \mu + 2\times \sigma$

$= 473 + 2\times 28 = 529$

almost 0.15% of students spent more amount is 529

6 0

3 years ago

PLEASE HELP FAST Segment PR and segment QS are diameters of circle U. Find measure of arc ST

kogti [31]

Answer:

Maybe 74

Step-by-step explanation:

42+64=106

180-106=74

5 0

3 years ago

Please help everything you need is on the picture.

satela [25.4K]

She would need to buy 75% of the dress Bc 100%-25% is 75%

3 0

2 years ago

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A gold, a silver, and a bronze medal are awarded in an Olympic event. In how many possible ways can the medals be awarded for a

RideAnS [48]

Answer:

720 possible ways

Step-by-step explanation:

The gold is awarded to the first position, the silver is awarded to the second position while the bronze is awarded to the third position.

The first position can be taken by any of the 10 runners

Now, the second position can be taken by remaining 9 runners

while the third position can be taken by the renaming 8 runners.

Thus, the number of ways in which these medals can be awarded = 10 * 9 * 8 = 720 ways

3 0

3 years ago

Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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