1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
netineya [11]
2 years ago
6

How many minutes will it take a car to go from a stop to 33 km/hr if it accelerates at 10 km/hr²

Physics
2 answers:
Ber [7]2 years ago
8 0

Answer:

33= 0+10 * t so t = 33 / 10 = 3.3 hrs

fomenos2 years ago
7 0

the answer is in the number 9.

You might be interested in
A 25kg chair initially at rest on a horizontal floor requires 165 N force to set it in motion. Once the chair is in motion, a 12
bazaltina [42]

The coefficient of static friction between the chair and the floor is 0.67

Explanation:

Given:

Weight of the chair = 25kg

Force = 165 N (F_applied)

Force = 127 N (F_max)

To find: Coefficient of static friction  

The “coefficient of static friction” between a chair and the floor is defined as the ration of maximum force to the normal force acting on the chair  

μ_s=F_{max}/F_{n}  

The F_n is equal to the weight multiplied by its gravity

∴F_{n}=mg  

Thus the coefficient of static friction changes as

μ_s=F_{max}/mg

μ_{s} = =165N/((25kg)\times(9.80 m/s^2 ) )

= 0.67

3 0
3 years ago
If the result of your calculation of a quantity has si units kg•m^2/s^2•C, that quantity could be
Novosadov [1.4K]
It would be Joules.
Workdone is measured in Joules.
Workdone = Force * distance
Force = mass * acceleration
          = kg      *  ms⁻²
          = kgms⁻²

Distance = m

So, Force * distance
       kgms⁻² * m

Apply laws of indices that says
x² * x³ = x²⁺³ = x⁵

Therefore, It would be kgm²s⁻²
m¹ * m¹ = m¹⁺¹ = m²
s⁻² is also = s / 2





4 0
3 years ago
Read 2 more answers
In the photoelectric effect, the greater the frequency of the illuminating light, the greater the:_______
TEA [102]

Answer:

B. Maximum velocity of ejected electrons.

Explanation:

The ejection of electrons form a metal surface when the metal surface is exposed to a monochromatic electromagnetic wave of sufficiently short wavelength or higher frequency (or equivalently, above a threshold frequency),  which leads to the enough energy of the wave to incident and get absorbed to the exposed surface emits electrons. This phenomenon is known as the photoelectric effect or photo-emission.

The minimum amount of energy required by a metal surface to eject an electron from its surface is called work function of metal surface.

The electrons thus emitted are called photo-electrons.

The current produced as a result is called photo electricity.

Energy of photon is given by:

E=h.\nu

where:

h = Planck's constant

\nu= frequency of the incident radiation.

8 0
3 years ago
lanet R47A is a spherical planet where the gravitational acceleration on the surface is 3.45 m/s2. A satellite orbitsPlanet R47A
qaws [65]

2.6×10^6\:\text{m}

Explanation:

The acceleration due to gravity g is defined as

g = G\dfrac{M}{R^2}

and solving for R, we find that

R = \sqrt{\dfrac{GM}{g}}\:\:\:\:\:\:\:(1)

We need the mass M of the planet first and we can do that by noting that the centripetal acceleration F_c experienced by the satellite is equal to the gravitational force F_G or

F_c = F_G \Rightarrow m\dfrac{v^2}{r} = G\dfrac{mM}{r^2}\:\:\:\:\:(2)

The orbital velocity <em>v</em> is the velocity of the satellite around the planet defined as

v = \dfrac{2\pi r}{T}

where <em>r</em><em> </em>is the radius of the satellite's orbit in meters and <em>T</em> is the period or the time it takes for the satellite to circle the planet in seconds. We can then rewrite Eqn(2) as

\dfrac{4\pi^2 r}{T^2} = G\dfrac{M}{r^2}

Solving for <em>M</em>, we get

M = \dfrac{4\pi^2 r^3}{GT^2}

Putting this expression back into Eqn(1), we get

R = \sqrt{\dfrac{G}{g}\left(\dfrac{4\pi^2 r^3}{GT^2}\right)}

\:\:\:\:=\dfrac{2\pi}{T}\sqrt{\dfrac{r^3}{g}}

\:\:\:\:=\dfrac{2\pi}{(1.44×10^4\:\text{s})}\sqrt{\dfrac{(5×10^6\:\text{m})^3}{(3.45\:\text{m/s}^2)}}

\:\:\:\:= 2.6×10^6\:\text{m}

5 0
3 years ago
Which if the following statements is true? A. Instantaneous acceleration is always changing. B. An object at rest has an instant
ycow [4]
B is the right one

hope this helps you
3 0
3 years ago
Other questions:
  • A newly discovered planet has a mean radius of 7380 km. A vehicle on the planet\'s surface is moving in the same direction as th
    8·1 answer
  • The pupil of the eye is the circular opening through which light enters. Its diameter can vary from about 8.00 mm to about 2.00
    8·1 answer
  • Gravity can be described as
    13·2 answers
  • Kyle has a mass of 54 kg and is jogging at a velocity of 3 m/s. What is Kyle’s kinetic energy?
    14·2 answers
  • Define an astronomical unit. Choose all that apply. a. 8.3 minutes Average distance from Earth to the Sun. b. Distance that ligh
    12·1 answer
  • Suppose the radius of the Earth is given to be 6378.01 km. Express the circumference of the Earth in m with 5 significant figure
    12·1 answer
  • 1.Two skaters, Evelyn and Lily, face each other on near frictionless ice. Evelyn has a mass of 57.4 kg, and Lily has a mass of 4
    7·1 answer
  • Why does lowering the temperature of an object increase its density
    7·1 answer
  • If we interpret the large, angular rocks to have originated from the outcrop at the top of the hill, we are using __________ rea
    14·1 answer
  • How is newton’s first law of motion used for a person in a stationary car during a car crash
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!