Answer:
Can see it in the pic
Explanation:
Can see it in the pic
How would you define compound
1 answer:
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The magnetic force acting on a charged particle moving perpendicular to the field is:
= qvB
is the magnetic force, q is the particle charge, v is the particle velocity, and B is the magnetic field strength.
The centripetal force acting on a particle moving in a circular path is:
= mv²/r
is the centripetal force, m is the mass, v is the particle velocity, and r is the radius of the circular path.
If the magnetic force is acting as the centripetal force, set equal to
and solve for v:
qvB = mv²/r
v = qBr/m
Due to the work-energy theorem, the work done on the proton by the potential difference V becomes the proton's kinetic energy:
W = KE
W is work, KE is kinetic energy
W = Vq
KE = 0.5mv²
Therefore:
Vq = 0.5mv²
Substitute v = qBr/m and solve for V:
V = 0.5qB²r²/m
Given values:
m = 1.67×10⁻²⁷kg (proton mass)
B = 0.750T
q = 1.60×10⁻¹⁹C (proton charge)
r = 1.84×10⁻²m
Plug in the values and solve for V:
V = (0.5)(1.60×10⁻¹⁹)(0.750)²(1.84×10⁻²)²/1.67×10⁻²⁷
V = 9120V
Answer:
t₁ - t₂ = 0.0011 s
Explanation:
given,
y(x, t) = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
now,
y m = 6 mm ω = 600 rad/s
y₁ = + 2.0 mm y₂ = -2 .0 mm
now,
2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
-2 = (6.0 mm) sin( kx + (600 rad/s)t + Φ)
so,
kx + (600 rad/s)t₁ + Φ = ......(1)
we have multiplied with π/180 to convert angle into radians
kx + (600 rad/s)t₂ + Φ = ......(2)
subtracting both the equation (1)-(2)
600(t₁-t₂) =
now,
t₁ - t₂ = 0.0011 s
time does any given point on the string take to move between displacements is equal to 0.0011 s
Answer:
Explanation:is in the picture below
