All categories

3 years ago

Mark the false statements.

Physics

1 answer:

UkoKoshka [18]3 years ago

6 0

Answer:

false statement are C , F , D.

Explanation:

false statement are C , F , D.

a) triple bond consist of two π bond and one sigma bond.

b) in double bond one bond is σ bond and one is π bond.

c) end to end overlapping is in σ bond and electron density in σ bond lie between the nuclei.

true statements are A, B , E.

π bond restrict rotation is correct and then the statement of bond formation between s orbital is σ bond.

You might be interested in

Order the sounds made by these sources from highest to lowest pitch.

Trava [24]

Answer:

motorcycle, telephone, piano, lawn mower

4 0

3 years ago

Learning Goal: To understand the nature of a sound wave, including its properties: frequency, wavelength, loudness, pitch, and t

Lady_Fox [76]

Answer:

Sound wave is a longitudinal wave that propagates in a medium

Explanation:

Part A: (C) Sound wave is propagation of pressure fluctuations in a medium.

Part B: (C) Pressure fluctuations travel along the direction of propagation of the sound wave.

Part C: (A) Yes air play a role in the propagation of the human voice from one end of the lecture hall to the other.

5 0

3 years ago

Elina [12.6K]

Answer:

The vertical distance that the ski jumper fell is 417.45 m.

Explanation:

Given;

initial horizontal velocity of the jumper, $V_x$ = 26 m/s

horizontal distance of the jumper, dx = 240 m

The time of the motion is given by;

dx = Vₓt

t = dx / Vₓ

t = 240 / 26

t = 9.23 s

The vertical distance traveled by the diver is given by;

$d_y = V_yt + \frac{1}{2}gt^2$

initial vertical velocity, $V_y$ , = 0

$d_y = \frac{1}{2}gt^2\\\\d_y = \frac{1}{2}(9.8)(9.23)^2\\\\d_y = 417.45 \ m$

Therefore, the vertical distance that the ski jumper fell is 417.45 m.

6 0

3 years ago

The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. (a) Find

lana66690 [7]

Answer:

lowest frequency = 535.93 Hz

distance between adjacent anti nodes is 4.25 cm

Explanation:

given data

length L = 32 cm = 0.32 m

to find out

frequency and distance between adjacent anti nodes

solution

we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s

lowest frequency will be = $\frac{v}{2L}$ ..............1

put here value in equation 1

lowest frequency will be = $\frac{343}{2(0.32)}$

lowest frequency = 535.93 Hz

and

we have given highest frequency f = 4000Hz

wavelength = $\frac{v}{f}$ ..............2

put here value

wavelength = $\frac{343}{4000}$

wavelength = 0.08575 m

so distance = $\frac{wavelength}{2}$ ..............3

distance = $\frac{0.08575}{2}$

distance = 0.0425 m

so distance between adjacent anti nodes is 4.25 cm

3 0

3 years ago

When a Lunar Module landed on the Moon, it used thrusters to slow its descent to the surface. When other spacecraft are returned

mote1985 [20]

A parachute is a device designed to generate a LOT of air resistance.
Parachutes do that very well in places where there's any air to work with.
There is no air on the Moon.

7 0

3 years ago