Parallel-plate capacitor has there fore formula is
<span>C=(<span>ϵ0</span>A)/d
putting values</span>C=(8.85*10^-12*pi*.05^2)/.00063
=1.1*10^-10F
then Q=CV=1.1*10^-10*1000=1.1*10^-7C
as
<span>η=Q/A</span><span>therefore
(1.1*10^-7)/(pi*.05^2)
=1.4*10^-5C/m^ our answer
hope this helps</span>
Answer:

Explanation:
The force of gravity acting on the satellite is given by:

where
G is the gravitational constant
is the Earth's mass
m is the mass of the satellite
r is the distance of the satellite from the Earth's centre
Here we have
m = 700 kg

Substituting into the equation, we find:

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>
Nuclear Fission s a power source with a very low environmental impact.
The spontaneous transformation of an unstable atomic nucleus into a lighter one, in which radiation is released in the form of alpha particles, beta particles, gamma rays, and other particles. The rate of decay of radioactive substances such as carbon 14 or uranium is measured in terms of their half-life .
Answer:
T = 4200N
Explanation:
When the submersible craft is at rest, the tension in the cable is 6000N.
With this information you can calculate the weight of the craft by summing the forces (the summation of the force is zero because the craft is at rest):

When the craft is going down with a constant speed, there is a drag force of 1800N. Then, by using the second Newton law you have:
(1)
Fd: drag force
The summation of the forces is zero because the craft moves with constant velocity, that is, there is no acceleration.
You calculate the new tension on the cable by solving the equation (1) for T:

hence, the tension is 4200N