11.Perfectly elastic,as in only this collision K.E is conserved,however momentum is conserved in both elastic and inelastic collisions.
9)must also be conserved.because there is eleastic collision.
8)unchanged.
7)dcreases as velocity changes from 0.5 to 0 m/s.
4)momentum
Answer:
Explanation:
Range= U²sin2theta/g
= 102²* sin (2*42)/9.8
= 1054.74m
Yes she will be abable to jump
The distance from the edge will be
(1054.74- 420)m
= 634.74m
Answer:
-639288.89 N/C
Explanation:
x = 21-6 = 13.5 cm
= 6 cm
= 21 cm
k = Coulomb constant =
The net electric field is given by
The net electric field is
Answer:
62.5m
Explanation:
Given parameters:
Mass of the ball = 0.5kg
Initial velocity = 35m/s
At the maximum height final velocity is 0m/s
Unknown:
Height of the rise of the ball = ?
Solution:
To solve this problem, we apply the right motion equation which is shown below;
v² = u² - 2gh
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
h is the height
Now insert the parameters and solve;
0² = 35² - 2(9.8)(h)
-1225 = -19.6h
h = 62.5m
True if you actually did it. false if you didn't