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An ideal spring is mounted horizontally, with its left end fixed. The force constant of the spring is 170 N/m. A glider of mass

gizmo_the_mogwai [7]

Answer:

Explanation:

First of all we shall find the velocity at equilibrium point of mass 1.2 kg .

It will be ω A , where ω is angular frequency and A is amplitude .

ω = √ ( k / m )

= √ (170 / 1.2 )

= 11.90 rad /s

amplitude A = .045 m

velocity at middle point ( maximum velocity ) = 11.9 x .045 m /s

= .5355 m /s

At middle point , no force acts so we can apply law of conservation of momentum

m₁ v₁ = ( m₁ + m₂ ) v

1.2 x .5355 = ( 1.2 + .48 ) x v

v = .3825 m /s

= 38.25 cm /s

Let new amplitude be A₁ .

1/2 m v² = 1/2 k A₁²

( 1.2 + .48 ) x v² = 170 x A₁²

( 1.2 + .48 ) x .3825² = 170 x A₁²

A₁ = .0379 m

New amplitude is .0379 m

7 0

3 years ago

How does the diameter of the disk of milky way galaxy compare to its thickness?

weqwewe [10]

The diameter is about 100 times as great as the thickness.

7 0

3 years ago

I need help ASAP I need to get this right plz plz plz!!!!!

Rina8888 [55]

The atomic nucleus consists of protons and neutrons.

Additional information:

Protons are positively charged particle and neutrons are negatively charged particle.

Hope this will help u...:)

3 0

3 years ago

Read 2 more answers

The diagram shows a position-time graph What is the displacement of the object

algol13

The object is moving, so at different times, it has different displacement. I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) . That's -1m .

5 0

2 years ago

A 2.0kg object is raised by a height of 0.5m.Calculate the energy raised in its gravitational potential energy store? G=9.8N/KG

notka56 [123]

Answer:

Gravitational potential energy stored is 9.8 J.

Given:

G = 9.8 $\frac{N}{kg}$

height = 0.5 m

mass = 2 kg

To find:

Gravitation Potential energy stored = ?

Formula used:

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Solution:

Potential energy of the object is given by,

Potential energy = mGh

m = mass

G = acceleration due to gravity

h = height

Potential energy = 2 × 9.8 × 0.5

Potential energy = 9.8 Joule

Gravitational potential energy stored is 9.8 J.

5 0

2 years ago

Who single I'mma stud fwm​

Who single I'mma stud fwm