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Rainbow [258]
3 years ago
14

Experiment to determine the refractive index of a glass prism FOCAL LENGTH = 9.5cm i° e° d° 30 43 69 40 41 61 45 39 56 50 37 48

65 41 37 plot a graph of d° against i° from the graph Determine; (i) the minimum deviation and the corresponding angle of incidence (ii) the maximum deviation and the corresponding angle of incidence n=sin⁡(A+D÷2)÷(sinA÷2) Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment. THANK YOU SO MUCH
Physics
1 answer:
yarga [219]3 years ago
3 0
We are given the data for the angle of incidence and angle of refraction.
The first part of the problem is to plot the deviation and the angle of incidence. The minimum deviation is 37 with 65 degrees as the corresponding angle of incidence. The maximum deviation is 69 with a corresponding angle of incidence of 30 degrees. It is not advisable to use small values for the angle of incidence since it would result to a higher deviation from Snell's Law.
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1 year ago
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ver shines light up to the surface of a flat glass-bottomed boat at an angle of 30 relative to the normal. If the index of refr
Free_Kalibri [48]

Answer:

\beta = 41.68°

Explanation:

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sin\alpha = \frac{n_w}{n_g}* sin30

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now applying snell's law between air and glass, so we have

\frac{n_g}{n_a} = \frac{sin\alpha}{sin\beta}

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7 0
3 years ago
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