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Rainbow [258]
2 years ago
14

Experiment to determine the refractive index of a glass prism FOCAL LENGTH = 9.5cm i° e° d° 30 43 69 40 41 61 45 39 56 50 37 48

65 41 37 plot a graph of d° against i° from the graph Determine; (i) the minimum deviation and the corresponding angle of incidence (ii) the maximum deviation and the corresponding angle of incidence n=sin⁡(A+D÷2)÷(sinA÷2) Determine the error in n and explain why it is not advisable to use small values of i° in performing this experiment. THANK YOU SO MUCH
Physics
1 answer:
yarga [219]2 years ago
3 0
We are given the data for the angle of incidence and angle of refraction.
The first part of the problem is to plot the deviation and the angle of incidence. The minimum deviation is 37 with 65 degrees as the corresponding angle of incidence. The maximum deviation is 69 with a corresponding angle of incidence of 30 degrees. It is not advisable to use small values for the angle of incidence since it would result to a higher deviation from Snell's Law.
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Which is not a factor that affects the pressure of a gas in a closed container?
maksim [4K]

it is size of of particles because it does not matter about the size in a closed container

7 0
3 years ago
you nose out another runner to win 100.000 m dash. if your total time for the race was 13.800 s and you aced out the other runne
sammy [17]

Your average speed was

(100 m) / (13.8 s) = 7.25 m/s .

If you finished 0.001s ahead of him, then at your average speed, that corresponds to

(7.25 m/s) x (0.001 s) = 0.00725 m

That's 7.25 millimeters ... about 0.28 of an inch !

NOTE:. I think this is only valid if your speed was a constant ~7.25 m/s all the way.

3 0
3 years ago
Starting from rest, a 2.3x10-4 kg flea springs straight upward. While the flea is pushing off from the ground, the ground exerts
Harman [31]

Answer:

3.13 m/s

Explanation:

From the question,

Since the flea spring started from rest,

Ek = W................... Equation 1

Where Ek = Kinetic Energy of the flea spring, W = work done on the flea spring.

But,

Ek = 1/2mv²............ Equation 2

Where m = mass of the flea spring, v = flea's speed when it leaves the ground.

substitute equation 2 into equation 1

1/2mv² = W.................... Equation 3

make v the subject of the equation

v = √(2W/m)................. Equation 4

Given: W = 3.6×10⁻⁴ J, m = 2.3×10⁻⁴ kg

Substitute into equation 4

v = √[2×3.6×10⁻⁴ )/2.3×10⁻⁴]

v = 7.2/2.3

v = 3.13 m/s

Hence the flea's speed when it leaves the ground  = 3.13 m/s

4 0
2 years ago
A camera lens focuses on an object 75.0 cm from the lensThe image forms 3.50 cm behind the lens. What is the magnification of th
N76 [4]

Answer:

7/150

Explanation:

The following data were obtained from the question:

Object distance (u) = 75cm

Image distance (v) = 3.5cm

Magnification (M) =..?

Magnification is simply defined as:

Magnification (M) = Image distance (v)/ object distance (u)

M = v /u

With the above formula, we can obtain the magnification of the image as follow:

M = v/u

M = 3.5/75

M = 7/150

Therefore, the magnification of the image is 7/150.

6 0
3 years ago
During the experiment it is determined that, as the cart rolls between two points on the track, the work done on the cart by the
natita [175]

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

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½mv₀² + W = ½mv₁²

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v₁ = 1.626991...

v₁ = 1.6 m/s

4 0
2 years ago
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