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2 years ago

Explain why position is a dependent variable in a position versus time graph.

Physics

1 answer:

fenix001 [56]2 years ago

7 0

Answer:

Explanation:

The position depends on the time. The longer the time, the further the distance.

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Where is potential energy the greatest on a rollercoaster?

lidiya [134]

On a roller coaster, the greatest potential energy is at the highest point of the roller coaster

4 0

3 years ago

A street light is on top of a 8 foot pole. Joe,

zubka84 [21]

8/4 = y/y-x

8y - 8x = 4y

y = 2x

y = 2 x 4

y = 8

Hope this helps

5 0

3 years ago

A transverse wave on a string has an amplitude a. A tiny spot on the string is colored red. As one cycle of the wave passes by

aliya0001 [1]

Answer:

Option D) 4A

Explanation:

As the cycle of the wave passes by, the amplitude gives the longest journey when the spot travels from the undistributed position. During each cycle the spot travels "Four times" .

Considering one of this cycle, if it begins to travel from it's undistributed position , there would be four movements i.e

* Upward movement through distance A

*Downward movement through distance A

*Downward again through distance A

*Upward through distance A.

Then it would travel back to its undistributed position held

4 0

2 years ago

A person drives 4 miles east and the. 3 miles west

qwelly [4]

If a person drives 4 miles east, then 3 miles west, here are the facts:

They are 1 mile away from where they started.

They have driven a total of 7 miles.

7 0

3 years ago

Four charges are on the four corners of a square. Q1 = +5μC, Q2 = -10μC, Q3 = +5μC, Q4 = -10μC. The side length of the square is

Marat540 [252]

Answer:

Explanation:

Electric field due to a point charge Q at a point at distance d is given by the relation

E = $\frac{K\times Q}{d^2}$

Since Q1 and Q2 are of the same magnitude and distance , so they will create eletric field of same magnitude. Similarly field due to rest of the charges will also be same.

The charges are situated on the corners of a square in such a way that

equal charges of Q1 and Q3 are situated on the diametrically opposite corners of the square. Fields due to these two charges will be equal and opposite in direction. Therefore net field due to these two charges will be zero.

On the same ground, we can say that field due to Q2 and Q4 at the centre will be equal and opposite and therefore they will cancel out each other. Net field at the centre will be zero

Overall, net field due to all the four charges will be zero

3 0

3 years ago