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4 years ago

5

When radioactive atoms decay, they give off radiation and ___ . A. heat energy B. poisonous gases C. ridge pushes D. p waves

2 answers:

expeople1 [14]4 years ago

7 0

D. P waves. gives you cancer

Sunny_sXe [5.5K]4 years ago

5 0

D pwave is the answer and thx

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At the Indianapolis 500, you can measure the speed of cars just by listening to the difference in pitch of the engine noise betw

allsm [11]

To develop this problem it is necessary to apply the concepts related to the Dopler effect.

The equation is defined by

$f_i = f_0 \frac{c}{c+v}$

Where

$f_h$ = Approaching velocities

$f_i$ = Receding velocities

c = Speed of sound

v = Emitter speed

And

$f_h = f_0 \frac{c}{c+v}$

Therefore using the values given we can find the velocity through,

$\frac{f_h}{f_0}=\frac{c-v}{c+v}$

$v = c(\frac{f_h-f_i}{f_h+f_i})$

Assuming the ratio above, we can use any f_h and f_i with the ratio 2.4 to 1

$v = 353(\frac{2.4-1}{2.4+1})$

$v = 145.35m/s$

Therefore the cars goes to 145.3m/s

7 0

3 years ago

At which position is the southern hemisphere experiencing spring?

atroni [7]

Hey! I know you've probably already finished the quiz already, but I just wanted to let you know the correct answer should be D. I wish I could tell you why, but I ended up getting that answer through a bit of trial and error myself... Anyway, good luck!

8 0

3 years ago

Read 2 more answers

In the Bohr model of the hydrogen atom, an electron moves in a circular path around a proton. The speed of the electron is appro

Alexxx [7]

Explanation:

It is given that,

Radius of the circular orbit, $r=0.53\times 10^{-10}\ m$

Speed of the electron, $v=2.2\times 10^6\ m/s$

Mass of the electron, $m=9.1\times 10^{-31}\ kg$

(a) The force acting on the electron is centripetal force. Its formula is given by :

$F=\dfrac{mv^2}{r}$

$F=\dfrac{9.1\times 10^{-31}\times (2.2\times 10^6)^2}{0.53\times 10^{-10}}$

$F=8.31\times 10^{-8}\ N$

(b) The centripetal acceleration of the electron is given by :

$a=\dfrac{v^2}{r}$

$a=\dfrac{(2.2\times 10^6)^2}{0.53\times 10^{-10}}$

$a=9.13\times 10^{22}\ m/s^2$

Hence, this is the required solution.

5 0

3 years ago

A centrifugal pump discharges 300 gpm against a head of 55 ft when the speed is 1500 rpm. The diameter of the impeller is 15.5 i

Ksivusya [100]

Answer: Question 1: Efficiency is 0.6944

Question 2: speed of similar pump is 2067rpm

Explanation:

Question 1:

Flow rate of pump 1 (Q1) = 300gpm

Flow rate of pump 2 (Q2) = 400gpm

Head of pump (H)= 55ft

Speed of pump1 (v1)= 1500rpm

Speed of pump2(v2) = ?

Diameter of impeller in pump 1= 15.5in = 0.3937m

Diameter of impeller in pump 2= 15in = 0.381

B.H.P= 6.0

Assuming cold water, S.G = 1.0

eff= (H x Q x S.G)/ 3960 x B.H.P

= (55x 300x 1)/3960x 6

= 0.6944

Question 2:

Q = A x V. (1)

A1 x v1 = A2 x V2. (2)

Since A1 = A2 = A ( since they are geometrically similar

A = Q1/V1 = Q2/V2. (3)

V1(m/s) = r x 2π x N(rpm)/60

= (0.3937x 2 x π x 1500)/2x 60

= 30.925m/s

Using equation (3)

V2 = (400 x 30.925)/300

= 41.2335m/s

To rpm:

N(rpm) = (60 x V(m/s))/2 x π x r

= (60 x 41.2335)/ 2× π × 0.1905

= 2067rpm.

6 0

3 years ago

Starting at t = 0 a net external force in the +x-direction is applied to an object that has mass 5.00 kg. A graph of the force a

Reptile [31]

Answer:

15√2 N

Explanation:

The acceleration is given by ...

a = F/m = 5t/5 = t . . . . meters/second^2

The velocity is the integral of acceleration:

v = ∫a·dt = (1/2)t^2

This will be 9 m/s when ...

9 = (1/2)t^2

t = √18 . . . . seconds

And the force at that time is ...

F = 5(√18) = 15√2 . . . . newtons

6 0

3 years ago