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olganol [36]
2 years ago
6

Technician A says that synthetic blend oil has the same service life as that of full synthetic oils. Technician B says that conv

entional oils have a shorter service life than that of synthetic oils. Who is correct
Engineering
1 answer:
stepladder [879]2 years ago
8 0

Answer:

In this case, both technicians are correct because conventional oil wont last as long as full-synthetic or full-synthetic high-mileage oil.   high-mileage or regular full-synthetic? I say go with the full-synthetic high-mileage oil because it can handle more miles than the regular low-mileage oil. it also wont damage ur motor unless ur motor requires  low-mileage oil.

Explanation:

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Ammonia enters the expansion valve of a refrigeration system at a pressure of 1.4 MPa and a temperature of 32degreeC and exits a
AveGali [126]

Answer:

the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %

Explanation:

given data

pressure p1 = 1.4 MPa = 14 bar

temperature t1 = 32°C

exit pressure = 0.08 MPa = 0.8 bar

to find out

the quality of the refrigerant exiting the expansion valve

solution

we know here refrigerant undergoes at throtting process so

h1 = h2

so by table A 14 at p1 = 14 bar

t1 ≤ Tsat

so we use equation here that is

h1 = hf(t1) = 332.17 kJ/kg

this value we get from table A13

so as h1 = h2

h1 = h(f2)  + x(2) * h(fg2)

so

exit quality  = \frac{h1 - h(f2)}{h(fg2)}

exit quality  = \frac{332.17- 9.04}{1382.73)}

so exit quality = 0.2337 = 23.37 %

the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %

5 0
3 years ago
A 132mm diameter solid circular section​
Ganezh [65]

Answer:

not sure if this helps but

5 0
3 years ago
A six-lane freeway (three lanes in each direction) in rolling terrain has 10-ft lanes and obstructions 5 ft from the right edge.
Anon25 [30]
That is too hard but u got that cuz i believe in you!!!
3 0
3 years ago
Fluid fills the space between two parallel plates. The differential equation that describes instantaneous fluid velocity for uns
USPshnik [31]

Answer:

u/v = S (y²w) / m sinwt + y/h

Explanation:

see attached image

3 0
3 years ago
A 3.0-m wide rectangular asphalt channel discharges 33.84 m^3/s of water with a depth of 2.0 m. What is the head loss in 100 m l
BaLLatris [955]

Answer:

Head loss in 100 m length equals 1.00 m.

Explanation:

The head loss in an open channel is calculated using manning's equation as follows

Q=\frac{1}{n}\frac{A^{5/3}}{P^{2/3}}S_{f}^{1/2}

For a asphalt rectangular channel we have

Area of flow = 3.0\times 2.0 = 6m^{2}

Wetted Perimeter = 3.0+2\times 2.0=7.0m

manning's roughness coefficient = 0.016

Applying values in the above equation we get

33.84=\frac{1}{0.016}\times \frac{6^{5/3}}{7^{2/3}}S_{f}^{1/2}\\\\\therefore S^{1/2}_{f}=0.1\\\\\therefore S_{f}=0.01

Now we know that

S_{f}=\frac{H_{L}}{L}\\\\\therefore H_{l}=0.01\times 100m=1.00m

8 0
3 years ago
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