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olganol [36]
2 years ago
6

Technician A says that synthetic blend oil has the same service life as that of full synthetic oils. Technician B says that conv

entional oils have a shorter service life than that of synthetic oils. Who is correct
Engineering
1 answer:
stepladder [879]2 years ago
8 0

Answer:

In this case, both technicians are correct because conventional oil wont last as long as full-synthetic or full-synthetic high-mileage oil.   high-mileage or regular full-synthetic? I say go with the full-synthetic high-mileage oil because it can handle more miles than the regular low-mileage oil. it also wont damage ur motor unless ur motor requires  low-mileage oil.

Explanation:

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A barometer reads a height of 78 cmHg. Express this atmospheric pressure to:
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  • A barometer reads a height of 78 cmHg. Express this atmospheric pressure to \large\mathsf{\red{\underline{Pascal(pa)}}}
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Water is stored in a tank which has vent open to the atmosphere. The water level is 1.0 m below the top the tank and the water i
sp2606 [1]

Answer:

6.99 x 10⁻³ m³ / s

Explanation:

Th e pressure difference at the two ends of the delivery pipe due to atmospheric pressure and water column will cause flow of water.

h = difference in the height of water column at two ends of delivery pipe

6 - 1 =  5 m

Velocity of flow of water

v = √2gh

= √ (2 x 9.8 x 5)

=  9.9 m /s

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7 0
3 years ago
A standard penetration test has been conducted on a coarse sand at a depth of 16 ft below the ground surface. The blow counts ob
scoray [572]

Solution :

Given :

The number of blows is given as :

0 - 6 inch = 4 blows

6 - 12 inch = 6 blows

12 - 18 inch = 6 blows

The vertical effective stress $=1500 \ lb/ft^2$

                                              $= 71.82 \ kN/m^2$

                                             $ \sim 72 \ kN/m^2 $

Now,

$N_1=N_0 \left(\frac{350}{\bar{\sigma}+70} \right)$

$N_1 = $ corrected N - value of overburden

$\bar{\sigma}=$ effective stress at level of test

0 - 6 inch, $N_1=4 \left(\frac{350}{72+70} \right)$

                      = 9.86

6 - 12 inch, $N_1=6 \left(\frac{350}{72+70} \right) $

                        = 14.8

12 - 18 inch, $N_1=6 \left(\frac{350}{72+70} \right) $

                         = 14.8

$N_{avg}=\frac{9.86+14.8+14.8}{3}$

       = 13.14

       = 13

8 0
2 years ago
Technician A says the small base circuit of a transistor controls current flow. Technician B says the small emitter circuit cont
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Answer:

A

Explanation:

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