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S_A_V [24]
3 years ago
14

What is the final volume, in milliliters, when 5.80 mL of 25.0 %(m/v) NaOH solution is diluted to give a 3.50 %(m/v) NaOH soluti

on.
Chemistry
1 answer:
Zigmanuir [339]3 years ago
7 0

Answer:

41.43 mL

Explanation:

First we <u>calculate the mass of NaOH in the original solution</u>:

  • 25.0 % m/v means that in 100 mL of solution, there are 25 grams of NaOH.
  • This means that in 5.80 mL, we would have (5.80 * 25/100) <u>1.45 grams of NaOH.</u>

Then we <u>calculate the volume of the diluted solution</u>, using the grams of NaOH (that remain the same throughout the dilution process):

  • 1.45 g NaOH * \frac{100 mL}{3.50gNaOH} = 41.43 mL
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When aqueous solutions of chromium(II) iodide and sodium phosphate are combined, solid chromium(II) phosphate and a solution of sodium iodide are formed. The molecular equation is:

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