A graph of real speed can have a section that's as steep as you want,
but it can never be a perfectly vertical section.
Any vertical line on a graph, even it it's only a tiny tiny section, means
that at that moment in time, the speed had many different values.
It also means that the speed took no time to change from one value to
another, and THAT would mean infinite acceleration.
Answer:
Nucleus
Explanation: I did the quiz and got it right. Have an amazing day!
Distance = speed / time
speed = 95 m/s
time = 3 s
distance = 95 / 3 m
displacement = 95/3 m or 32 m (2 s.f.)
Answer:
a) ![p_i=1.568\hat{i}+0.752 \hat{j}](https://tex.z-dn.net/?f=p_i%3D1.568%5Chat%7Bi%7D%2B0.752%20%5Chat%7Bj%7D)
b) ![v_{fx}=1.668\ m.s^{-1}](https://tex.z-dn.net/?f=v_%7Bfx%7D%3D1.668%5C%20m.s%5E%7B-1%7D)
c) ![v_{fy}=0.7999\ m.s^{-1}](https://tex.z-dn.net/?f=v_%7Bfy%7D%3D0.7999%5C%20m.s%5E%7B-1%7D)
Explanation:
Given masses:
![m_1=0.49\ kg](https://tex.z-dn.net/?f=m_1%3D0.49%5C%20kg)
![m_2=0.47\ kg](https://tex.z-dn.net/?f=m_2%3D0.47%5C%20kg)
Velocity of mass 1, ![v_1=3.2 \hat{i}\ m.s^{-1}](https://tex.z-dn.net/?f=v_1%3D3.2%20%5Chat%7Bi%7D%5C%20m.s%5E%7B-1%7D)
Velocity of mass 2, ![v_2=1.6 \hat{j}\ m.s^{-1}](https://tex.z-dn.net/?f=v_2%3D1.6%20%5Chat%7Bj%7D%5C%20m.s%5E%7B-1%7D)
a)
Initial momentum:
![p_i=m_1.v_1+m_2.v_2](https://tex.z-dn.net/?f=p_i%3Dm_1.v_1%2Bm_2.v_2)
![p_i=0.49\times 3.2 \hat{i}+0.47\times 1.6 \hat{j}](https://tex.z-dn.net/?f=p_i%3D0.49%5Ctimes%203.2%20%5Chat%7Bi%7D%2B0.47%5Ctimes%201.6%20%5Chat%7Bj%7D)
![p_i=1.568\hat{i}+0.752 \hat{j}](https://tex.z-dn.net/?f=p_i%3D1.568%5Chat%7Bi%7D%2B0.752%20%5Chat%7Bj%7D)
b)
magnitude of initial momentum:
![p_i=\sqrt{1.568^2+0.752 ^2}](https://tex.z-dn.net/?f=p_i%3D%5Csqrt%7B1.568%5E2%2B0.752%20%5E2%7D)
![p_i=1.739\ kg.m.s^{-1}](https://tex.z-dn.net/?f=p_i%3D1.739%5C%20kg.m.s%5E%7B-1%7D)
From the conservation of momentum:
![p_f=p_i](https://tex.z-dn.net/?f=p_f%3Dp_i)
![m_f.v_f=1.739](https://tex.z-dn.net/?f=m_f.v_f%3D1.739)
![v_f=\frac{1.739}{0.49+0.47}](https://tex.z-dn.net/?f=v_f%3D%5Cfrac%7B1.739%7D%7B0.49%2B0.47%7D)
is the magnitude of final velocity.
Direction of final velocity will be in the direction of momentum:
![tan\theta=\frac{0.752 }{1.568}](https://tex.z-dn.net/?f=tan%5Ctheta%3D%5Cfrac%7B0.752%20%7D%7B1.568%7D)
![\theta=25.62^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D25.62%5E%7B%5Ccirc%7D)
![\therefore v_{fx}=1.85\ cos25.62^{\circ}](https://tex.z-dn.net/?f=%5Ctherefore%20v_%7Bfx%7D%3D1.85%5C%20cos25.62%5E%7B%5Ccirc%7D)
![v_{fx}=1.668\ m.s^{-1}](https://tex.z-dn.net/?f=v_%7Bfx%7D%3D1.668%5C%20m.s%5E%7B-1%7D)
c)
Vertical component of final velocity:
![v_{fy}=1.85\ sin 25.62^{\circ}](https://tex.z-dn.net/?f=v_%7Bfy%7D%3D1.85%5C%20sin%2025.62%5E%7B%5Ccirc%7D)
![v_{fy}=0.7999\ m.s^{-1}](https://tex.z-dn.net/?f=v_%7Bfy%7D%3D0.7999%5C%20m.s%5E%7B-1%7D)