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Nastasia [14]
3 years ago
15

What is the formula for finding the frequency in longitudinal waves and also transverse waves? Thank you!

Physics
2 answers:
sweet [91]3 years ago
5 0

Frequency of any wave =

(the SPEED of the wave)/(wavelength)

insens350 [35]3 years ago
3 0
The frequency of a wave is the number of wavelengths per second. The period of a longitudinal wave is the time taken by the wave to move one wavelength. As for transverse waves, the symbol T is used to represent period and period is measured in seconds 
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a wheel 0.35m in diameter rotates at 2200rpm. calculate its angular velocity in rad/s and its linear speed and acceleration of a
bazaltina [42]

Answer:

( Angular Velocity = ( About ) 230 rad / s,

( Linear Speed = ( About ) 40.25 m / s,

( Acceleration = ( About ) 9290 m / s^2

Explanation:

Here we want the angular velocity in radians per second, the linear velocity and acceleration.

The diameter = .35 meters, and thus we can conclude that the radius be half of that, or .175 meters. For part ( a ), or the calculation of the angular velocity, it is given that the diameter rotates at 2200 revolutions per minute - but we need to convert this into radians per second.

We can say that there are 2π radians for every minute, and for every minute there are 60 seconds. Therefore -

( a ) w = 2,200 rpm( 2π rads / rev )( 1 min / 60 sec )...

Hence, w = ( About ) 230 rad / s

_____

For this second part we can calculate the the linear velocity by multiplying the angular velocity ( omega ) by the radius r -

( b ) v = w( r ) - Substitute,

v = ( 230 rad / sec )( .175 m )...

v = ( About ) 40.25 m / s

_____

And for this last bit here, to find the acceleration we can simply take the angular velocity ( omega ) squared, by the radius r -

( c ) a_{rad} = w^2( r ),

a_{rad} = ( ( 230 rad / sec )^2 )( .175 m )...

a_{rad} = ( About ) 9290 m / s^2

7 0
3 years ago
Is everyone in your class able to hear a quiet sound equally well?
Sergio039 [100]

Answer:

No

Explanation:

Loudness describes how people perceive sound (see loudness). ... If people could hear equally well at all frequencies, the contour lines would be flat because the same measured sound intensity would be perceived to be equally loud regardless of the sound frequency. In fact, people do not hear as well at low frequencies.

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inna [77]
The net force is 22.8-2.3 or 20.5 N
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3 years ago
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elena55 [62]

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