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3 years ago

What do we call the average motion of moving atoms and molecules in the atmosphere?

1 answer:

5 0

Kinetic and potential energies are found in all objects. If an object is moving, it is said to have kinetic energy (KE). Potential energy (PE) is energy that is "stored" because of the position and/or arrangement of the object.

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What is the equation for finding the acceleration of an object moving in a straight line?

lapo4ka [179]

The equations to find the acceleration are the suvat equations:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as\\s=(\frac{u+v}{2})t$

Explanation:

The acceleration of an object is the rate if change in velocity of the object. It is calculated as

$a=\frac{v-u}{t}$

where

v is the final velocity of the object

u is the initial velocity

t is the time elapsed

For an object moving in a straight line at constant acceleration, there are several equations that can be used to find the acceleration: they are called suvat equations. They are the following:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as\\s=(\frac{u+v}{2})t$

where

u is the initial velocity

v is the final velocity

t is the time

s is the distance covered

a is the acceleration

Therefore, any of the above equations can be used to calculate the acceleration.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0

3 years ago

Whats the difference between kinetic and potential energy?

damaskus [11]

Kinetic energy is energy in motion and potential energy is stored energy

5 0

3 years ago

A golf ball is released from rest from the top of a very tall building. Choose a coordinate system whose origin is at the starti

Zigmanuir [339]

Answer:

Velocity of the ball after 3.04 (s) = 29.79 (m/s)

Explanation:

From the free fall movement we have the following formulas: $Vf^{2} = Vo^{2} - 2gh$ and $h=Vo*t - \frac{g*t^{2} }{2}$ , First we need to find the height to time iqual to 3.04 s using the formula: $h=Vo*t - \frac{g*t^{2} }{2}$ and remember that golf ball was released from the rest (Vo= 0 (m/s)) so $h= (0 (m/s))*(3.04 (s)) - \frac{9.8 (m/s^2)*(3.04 (s))^{2} }{2}$ , we get: h = -45.28 (m) with the height that we have got, now the velocity of the ball is calculate using $Vf^{2} = Vo^{2} - 2gh$ solving for Vf, we get: $Vf = \sqrt{Vo^{2}-2*g*h }$ replacing the values given $Vf = \sqrt{(0 m/s)^{2}-2*(9.8 m/s^2)*(-45.28 m) }$ , so we get: Vf = 29.79 (m/s).

5 0

3 years ago

Read 2 more answers

A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the d

timofeeve [1]

Perpendicular acceleration:
F = ma
a = 4 / 2 = 2 m/s²

Perpendicular distance:

s = ut + 1/2 at²
s = 0 x 4 + 1/2 x 2 x 4²
s = 16 m

Horizontal distance:
s = ut
= 3 x 4
= 12 m

Total distance = √(12² + 16²)
= 20 m.

3 0

3 years ago

How long does it take to travel to Mercury while going 100,000 km per hour?

Bond [772]

It Would Take Aprroximately 1000 Years.

6 0

3 years ago