The half-life of phosphorus-32 is 14.26 days. calculate its decay constant. express the decay constant numerically in inverse da
2 answers:
The decay constant(λ) = <u>0.0486/day</u>
<h3>Further explanation</h3>The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
The half-life can be expressed in a decay constant( λ)
The half-life of phosphorus-32 is 14.26 days
Then : t 1/2 = 14.26 days
The identity of the missing nucleus
the process of radioactive decay
nuclear fusion and nuclear fission reactions
the product of radioactive decay
You might be interested in
Answer: The ground-state electronic configuration of
1)
2)
Explanation: The electronic configuration of elements is defined as the distribution of electrons around the nucleus of that element. It depends on the atomic number of the element.
Atomic number of the element = Number of electrons.
- For Ru-element
Atomic number = 44
Number of electrons = 44
Electronic configuration of Ru-element =
To form , 2 electrons are released from the neutral Ru-element.
So, the electronic configuration of
- For W-element
Atomic number = 74
Number of electrons = 74
Electronic configuration of W-element =
To form , 3 electrons are released from the neutral W-element.
So, the electronic configuration of