The half-life of phosphorus-32 is 14.26 days. calculate its decay constant. express the decay constant numerically in inverse da
2 answers:
The decay constant(λ) = <u>0.0486/day</u>
<h3>Further explanation</h3>The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
The half-life can be expressed in a decay constant( λ)
The half-life of phosphorus-32 is 14.26 days
Then : t 1/2 = 14.26 days
The identity of the missing nucleus
the process of radioactive decay
nuclear fusion and nuclear fission reactions
the product of radioactive decay
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Lewis structures refers to the diagrams used to signify the bonding between the atoms of a molecule and the lone pair of electrons, which may prevail in the molecule. These structures are drawn on the basis of the formal charge of each atom within the ion or molecule.
The formal charge refers to the charge assigned to an atom in a molecule, which all the electrons are shared equivalently amongst the atoms regardless of its electronegativity.
The rule for formal charge calculation is,
Formal charge = no of valency shell electron - 1/2 of the no of shared pair electron - no of lone pair electron.
So, in this case, the formal charge of P = 5 - 1/2 (10) - 0 = 0
The valence shell of P have 5 electrons. The total 5 bond is there in the given composition, so total 10 bonding electron, and there is no lone pair of electron on P atom. So, formal charge of P is 0.
