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Vikki [24]
3 years ago
10

The half-life of phosphorus-32 is 14.26 days. calculate its decay constant. express the decay constant numerically in inverse da

ys.
Chemistry
2 answers:
zepelin [54]3 years ago
8 0
When this is the first order reaction of the radioactive decay:

and according to the first order rate equation:

㏑(Ao/A) = K t

and when Ao = is the starting concentration

and A = is the concentration at time t

and K is the rate constant 

t is the elapsed time = 14.26 days

for 1 half-life ∴ Ao/A = 2

by substitution:

㏑2 = K * 14.26 days

∴ K = 0.0486 days^-1
PolarNik [594]3 years ago
5 0

The decay constant(λ) = <u>0.0486/day</u>

<h3>Further explanation</h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles

General formulas used in decay:

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

The half-life can be expressed in a decay constant( λ)

\displaystyle t_ {1/2} = {\dfrac {\ln (2)} {\lambda}}

The half-life of phosphorus-32 is 14.26 days

Then : t 1/2 = 14.26 days

\rm \lambda=\dfrac{ln\:2}{14.26}\\\\\lambda=0.0486/day

<h3>Learn more</h3>

The identity of the missing nucleus

brainly.com/question/4207569

the process of radioactive decay

brainly.com/question/1770619

nuclear fusion and nuclear fission reactions

brainly.com/question/1949468

the product of radioactive decay

brainly.com/question/6029197

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Answer: (a). T = 38.2 °C     (b). V = 1.3392 cm³     (c). ii and iii  

Explanation:

this is quite easy to solve, i will give a step by step analysis to solving this problem.

(a). from the question we have that;

the Mole fraction of Nitrogen, yи₂ = 0.1

Also the Mole fraction of Water, yн₂o = 0.1

We know that the vapor pressure is equal to the partial pressure because the vapor tends to condense at due point.

ρн₂o = ṗн₂o

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(b). We have to calculate the total moles of gas mixture in a 30 litre flask;

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   n = [500(mmHG) × 30L] / [62.36(mmHGL/mol K) × 323.15K] = 0.744 mol

Moles of H₂O(v) is 0.1(0.744) = 0.0744 mol

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we have that the moles of water condensed is 0.0744 mol i.e the water vapor  in the flask is condensed

Vн₂o = 0.0744 × 18 / 1 (g/cm³)

Vн₂o = 1.3392 cm³

Therefore, the  volume of the liquid water is 1.3392 cm³

(3). (ii) and (iii)

The absolute pressure of the gas and The partial pressure of water in the gas would change if the barometric pressure drops.

cheers i hope this helps!!!!

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