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2 years ago

Hhhhhheeeeeellllllppppp me ffffaaaßstttt ananaanaanswswwwwweeeerrrr

Chemistry

2 answers:

sammy [17]2 years ago

8 0

Answer:

◎Bacterial diseases

◎Mycoplasmosis (CRD, Air sac, Sinusitis)

◎Fowl Cholera

◎Necrotic Enteritis

◎Ulcerative Enteritis (Quail disease)

◎Pullorum Disease

◎Fowl

◎Botulism

◎Infectious Coryza

◎Omphalitis

◎Erysipelas

◎Parasitic diseases (internal)

◎Parasitic diseases (external)

◎Infectious Bronchitis

◎Viral diseases

◎Newcastle Disease

◎Quail Bronchitis

◎Lymphoid Leukosis

◎Marek's Disease (Visceral Leukosis)

◎Infectious Bursal Disease (Gumboro)

Explanation:

LenKa [72]2 years ago

3 0

Answer:

Diseases of Poultry
a. ESCHERICHIA COLI INFECTIONS.
b. SALMONELLOSES.
c. PARATYPHOID INFECTIONS.
d. FOWL CHOLERA.
e. RIEMERELLA ANATIPESTIFER INFECTIONS.MYCOPLASMA.
f. NECROTIC ENTERITIS.
g. CHOLANGIOHEPATITIS IN BROILER CHICKENS.

Explanation:

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Part a use these data to calculate the heat of hydrogenation of buta-1,3-diene to butane. c4h6(g)+2h2(g)→c4h10(g)

Reptile [31]

Answer: The heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

Explanation:

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_{(product)}]-\sum [n\times \Delta H_{(reactant)}]$

For the given chemical reaction:

$C_4H_6(g)+2H_2(g)\rightarrow C_4H_{10}(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(1\times \Delta H_{(C_4H_{10})})]-[(1\times \Delta H_{(C_4H_6)})+(2\times \Delta H_{(H_2)})]$

We are given:

$\Delta H_{(C_4H_{10})}=-2877.6kJ/mol\\\Delta H_{(C_4H_6)}=-2540.2kJ/mol\\\Delta H_{(H_2)}=-285.8kJ/mol$

Putting values in above equation, we get:

$\Delta H_{rxn}=[(1\times (-2877.6))]-[(1\times (-2540.2))+(2\times (-285.8))]\\\\\Delta H_{rxn}=234.2J$

Hence, the heat of hydrogenation of the reaction is coming out to be 234.2 kJ.

4 0

2 years ago

GuDViN [60]

Answer:

A phosphorus atom forms a P3- ion by gaining three electrons.

here

4 0

2 years ago

What color would litmus paper turn in a solution of baking soda? Explain your answer in terms of pH.

madam [21]

Blue

When red litmus paper comes into contact with any alkaline substance, it turns blue. Some examples of alkaline substances are ammonia gas, milk of magnesia, baking soda and limewater.

3 0

2 years ago

Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

barxatty [35]

Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2. $Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.The electron affinity of $Mg^{2+}$ is zero.

4. $O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

Explanation:

Electron affinity:

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

Ionization energy:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

The electronic configuration of Mg: $1s^{2}2s^{2}2p^{6}3s^{2}$

By the removal of two electrons from a magnesium element we get $Mg^{2+}$ ion.

$Mg^{2+}$ has inert gas configuration i.e, $1s^{2}2s^{2}2p^{6}$

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of $Mg^{2+}$ is zero.

The ionization energy of $O^{2-}$ is follows.

$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

3 0

3 years ago

Transferring or sharing electrons between atoms forms

Brums [2.3K]

Transferring or sharing electrons between atoms forms a covalent bond. Covalent bonding is when atoms share electrons. It is a chemical bond that involves the sharing of electron pairs. These pairs are called bonding pairs. Examples of compounds that has covalent bonds are CO2, organic compounds, lipids and proteins.

6 0

3 years ago