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sveticcg [70]
2 years ago
12

Hhhhhheeeeeellllllppppp me ffffaaaßstttt ananaanaanswswwwwweeeerrrr

Chemistry
2 answers:
sammy [17]2 years ago
8 0

Answer:

◎Bacterial diseases

◎Mycoplasmosis (CRD, Air sac, Sinusitis)

◎Fowl Cholera

◎Necrotic Enteritis

◎Ulcerative Enteritis (Quail disease)

◎Pullorum Disease

◎Fowl

◎Botulism

◎Infectious Coryza

◎Omphalitis

◎Erysipelas

◎Parasitic diseases (internal)

◎Parasitic diseases (external)

◎Infectious Bronchitis

◎Viral diseases

◎Newcastle Disease

◎Quail Bronchitis

◎Lymphoid Leukosis

◎Marek's Disease (Visceral Leukosis)

◎Infectious Bursal Disease (Gumboro)

Explanation:

:)

LenKa [72]2 years ago
3 0

Answer:

Diseases of Poultry
a. ESCHERICHIA COLI INFECTIONS.
b. SALMONELLOSES.
c. PARATYPHOID INFECTIONS.
d. FOWL CHOLERA.
e. RIEMERELLA ANATIPESTIFER INFECTIONS.MYCOPLASMA.
f. NECROTIC ENTERITIS.
g. CHOLANGIOHEPATITIS IN BROILER CHICKENS.

Explanation:

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andrey2020 [161]
I think ionic hope it helps
7 0
3 years ago
Be sure to answer all parts. Hydrogen iodide decomposes according to the reaction 2 HI(g) ⇌ H2(g) + I2(g) A sealed 1.50−L contai
Zarrin [17]

Answer : The concentration of HI and I_2 at equilibrium is, 0.0158 M and 0.00302 M respectively.

Explanation :

First we have to calculate the concentration of H_2, I_2\text{ and }HI

\text{Concentration of }H_2=\frac{\text{Moles of }H_2}{\text{Volume of solution}}=\frac{0.00623mol}{1.50L}=0.00415M

\text{Concentration of }I_2=\frac{\text{Moles of }I_2}{\text{Volume of solution}}=\frac{0.00414mol}{1.50L}=0.00276M

\text{Concentration of }HI=\frac{\text{Moles of }HI}{\text{Volume of solution}}=\frac{0.0244mol}{1.50L}=0.0163M

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

                            2HI(g)\rightleftharpoons H_2(g)+I_2(g)

Initial conc.      0.0163     0.00415      0.00276

At eqm.        (0.0163-2x) (0.00415+x)  (0.00276+x)

As we are given:

Concentration of H_2 at equilibrium = 0.00467 M

That means,

(0.00415+x) = 0.00467

x = 0.00026 M

Concentration of HI at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M

Concentration of I_2 at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M

8 0
3 years ago
What is cation and anion for<br> CrS2
maksim [4K]
Cation - Cr 4+
Anion - S ^ 2-

Chromium sulfide
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4 0
1 year ago
If an object has a mass of 3500 mg what is the mass in kg? Show detailed work
dangina [55]
The answer is 0.0035

In order to figure out kg, you have to know that 1 milligram is equal to 1/100000 kilograms. You take the amount of mg's that you have, which is 3500, and divide it by 1000000 which will give you your answer.

3500/1000000= 0.0035 kg
7 0
3 years ago
Why is it necessary to adjust the height of the graduated cylinder when measuring the volume of CO2 (g) produced? What type of e
kolezko [41]

Explanation:

This process ensures that the pressure inside of the graduated cylinder is the same as the atmospheric pressure in the room.

Suppose the level of water inside and outside the cylinder is same, pressure stays the same. Therefore, total pressure of the is made equal to atmospheric pressure by adjusting the height of cylinder. it is done till the water level is equal.

8 0
3 years ago
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