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-BARSIC- [3]
3 years ago
5

7) A block of wood

Chemistry
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

Explanation:

7) A block of wood

has a length of 10.2

cm, a width of 6 cm

and a height of 4.1

cm. The wood has

a total mass of 179

grams. What is the

volume of the

wood and what is

the density of the

wood?

volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3

DENSITY = M/V = 179gm/250.92 cm^3

=0.713 gm/cm^3

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Answer ( 3 ) :

<span>conversion of matter to energy .
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4 0
3 years ago
A geologist is studying the shore along a river. She finds a pile of rocks at the base of a riverbank. These broken rock pieces
Dmitry_Shevchenko [17]

The scientist who studies the earth constituent like solids, gas and liquid is called a geologist. Weathering and erosion are the correct blanks.

<h3>What are weathering and erosion?</h3>

The process of the deterioration of any solid particles like minerals, soils and rocks is called weathering. It occurs due to biochemical substances, atmospheric gases and water pressure.

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7 0
2 years ago
How many phases are in a homogeneous mixture??
Mars2501 [29]
Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one.  <span />
7 0
3 years ago
Read 2 more answers
A neutral atom has the same number of _____ in it’s nucleus as____ in its electron cloud
rusak2 [61]

Answer:

the neutul atom has the same number of protons in its neclues as positive in its electron cloud#

Explanation:

8 0
3 years ago
a gas occupies 600.0 ml at 20.00 degrees C and 70.00kPa what will be the pressure at 40.00 degrees C and 150.0mL?
Zina [86]

Answer:

P₂ = 299.11 KPa

Explanation:

Given data:

Initial volume = 600 mL

Initial pressure = 70.00 KPa

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 40°C (40+273 = 313 K)

Final volume = 150.0 mL

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ =  70 KPa × 600 mL × 313 K / 293K ×150 mL  

P₂ = 13146000 KPa .mL. K /43950 K.mL

P₂ = 299.11 KPa

4 0
2 years ago
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