The given compound 1-bromo-1-chlorobutane is an optically active compound .
Because this compound does not have plane of symmetry (POS) and center of symmetry (COS) i.e. does not have di-symmetry . And also forms non superimposable mirror image . the compound is optically active .
It has chiral center.
Here , the chiral carbon is bonded to 4 distinct groups such as : chlorine , bromine , hydrogen and propyl .
<h3>What is di-symmetry?</h3>
Di-symmetry is that which have no center of symmetry and plane of symmetry and alternate axis of symmetry .
<h3>Chiral center :</h3>
Have Sp3 hybridized center (4sigma bond ) .
4 distinct group is attached to the chiral atom. form non -superimposable mirror image .
<h3>What is optical isomerism ?</h3>
Same molecular formula and same structural formula . also have same physical and chemical properties .
They differ in their behavior towards plane polarized light (ppl) .
Learn more about chiral center here:
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The oxidation number of Mn is 0. Details about oxidation number can be found below.
<h3>What is oxidation number?</h3>
Oxidation number is the hypothetical charge of an atom within a molecule.
However, when an atom exists independently as an element, the oxidation number of such element is 0.
The oxidation number is assigned to an atom in a element/compound. It can either be +, -, or 0 and it tells us if electrons are lost or gained.
Therefore, according to this question, the oxidation number of Mn is 0.
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The half-life of carbon 14 is 5,730 years<span>.
</span>The half-life of uranium-238 is about 4.5 billion years
<span>the half-life of uranium-235 </span>about 700 million years<span>,
</span>the half-life of carbon 14 is 5,730 years<span>.</span>
Answer:
The rate is 
Explanation:
Stoichiometry
Kinetics
![-r_{A}=k \times [CH_{3}Cl] \times [NaOH]](https://tex.z-dn.net/?f=-r_%7BA%7D%3Dk%20%5Ctimes%20%5BCH_%7B3%7DCl%5D%20%5Ctimes%20%5BNaOH%5D%20)
The rate constant K can be calculated by replacing with the initial data
![1 \times 10^{-4}\frac{mole}{Ls}=k \times [0,2M] \times [1,0M] =5 \times 10^{-4}\frac{L}{mole s}](https://tex.z-dn.net/?f=%201%20%5Ctimes%2010%5E%7B-4%7D%5Cfrac%7Bmole%7D%7BLs%7D%3Dk%20%5Ctimes%20%5B0%2C2M%5D%20%5Ctimes%20%5B1%2C0M%5D%20%20%3D5%20%5Ctimes%2010%5E%7B-4%7D%5Cfrac%7BL%7D%7Bmole%20s%7D)
Taking as a base of calculus 1L, when half of the 
is consumed the mixture is composed by
(half is consumed)
(by stoicheometry)
Then, the rate is
The reaction rate decreases because there’s a smaller concentration of reactives.
