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-BARSIC- [3]
3 years ago
5

7) A block of wood

Chemistry
1 answer:
melamori03 [73]3 years ago
5 0

Answer:

Explanation:

7) A block of wood

has a length of 10.2

cm, a width of 6 cm

and a height of 4.1

cm. The wood has

a total mass of 179

grams. What is the

volume of the

wood and what is

the density of the

wood?

volume = L XW XH=10.2 X 6 X4.1 =250.92cm^3

DENSITY = M/V = 179gm/250.92 cm^3

=0.713 gm/cm^3

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Ozone(O3) number of atoms
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As the O3 suggests, the Ozone molecule is made up of 3 Oxygen atoms.
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3 years ago
. In which reaction is nitric acid acting as an oxidising agent?
Talja [164]

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

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3 years ago
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Chemistry question please help!!
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3 years ago
a doctor's order is 0.125 g of ampicillin. the liquid suspension on hand contains 250 mg/5.0 ml. how many milliliters of the sus
disa [49]
0.125 g=(0.125 g)(1000 mg/1g)=125 mg.

Then, we need 125 mg of ampicillin.
5 ml of  liquid suspension contains 250 mg of ampicilling , therefore:

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5 0
4 years ago
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The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

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Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
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