Why does the magnet rotate in an AC motor?

An object moves with a speed of 30 km/h for 15 minutes and then with a speed of 60km/h for the next 15 minutes. Find the total d

Finger [1]

Answer:

Total distance = 22.5 kilometers

Explanation:

Let the first distance be A.

Let the second distance be B

Given the following data;

Speed A = 30km/h

Time A = 15 minutes to hours = 15/60 = 0.25 hour

Speed B = 60km/h

Time B = 15 minutes to hours = 15/60 = 0.25 hour

Now, to find the respective distance traveled;

Distance A = speed A * time A

Distance A = 30 * 0.25

Distance A = 7.5 km

Distance B = speed B * time B

Distance B = 60 * 0.25

Distance B = 15 km

Next, we calculate the total distance traveled;

Total distance = Distance A + distance B

Total distance = 7.5 + 15

Total distance = 22.5 kilometers.

Therefore, the total distance covered by the object is 22.5 kilometers.

5 0

3 years ago

A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha

allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

$d=2.2i+cj$

While the force applied on the particle is

$F=3.2i-3.8 j$

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

$W=F\cdot d$ (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

$0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85$

b)

In this problem, the work done on the particle is

$W=4.0 J$

The force and displacement are still

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

$W=F\cdot d$

$4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8$

c)

In this problem instead, the work done on the particle is negative:

$W=-1.8 J$

As before, the force and displacement are

$d=2.2i+cj$ (displacement)

$F=3.2i-3.8 j$ (force)

And so again, we calculate the scalar product between force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

$W=F\cdot d$

$-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33$

7 0

3 years ago

A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direct

-Dominant- [34]

Answer:

The velocity of the other fragment immediately following the explosion is v .

Explanation:

Given :

Mass of original shell , m .

Velocity of shell , + v .

Now , the particle explodes into two half parts , i.e $\dfrac{m}{2}$ .

Since , no eternal force is applied in the particle .

Therefore , its momentum will be conserved .

So , Final momentum = Initial momentum

$mv=\dfrac{mv}{2}+\dfrac{mu}{2}\\\\u=v$

The velocity of the other fragment immediately following the explosion is v .

4 0

3 years ago

15) The diagram below represents the sequence of events (steps 1 through 10) resulting in the production of a D' meson and a D*

zubka84 [21]

A statement which describes the changes that occur in this sequence of events is: 2. matter is converted into energy and then energy is converted into matter.

<h3>What is the law of conservation of matter?</h3>

The law of conservation of matter (LOCOM) states that mass can neither be created nor destroyed in any chemical reaction.

Similarly, the energy possessed by a matter can neither be created nor destroyed, but it can only be converted from one energy form to another.

In this context, we can logically deduce that a statement which best describes the changes that occur in this sequence of events is that matter is converted into energy and subsequently, energy is converted into matter.

Read more on matter here: brainly.com/question/24783543

#SPJ1

3 0

2 years ago

A 77.3 g mass is attached to a horizontal spring with a spring constant of 12.5 N/m and released from rest with an amplitude of

DENIUS [597]

Answer:

speed of the mass is 3.546106 m / s

Explanation:

given data

mass = 77.3 g = 77.3 × $10^{-3}$ kg

spring constant k = 12.5 N/m

amplitude A = 38.9 cm = 38.9 × $10^{-2}$ m

to find out

the speed of the mass

solution

we will apply here conservation energy that is

K.E + P.E = Total energy ..................1

so that Total energy = K.E max = P.E max

we know amplitude so we find out first P.E max that is

PE max = K.E + P.E

(1/2)kA² = (1/2)mv² + (1/2)kx²

kA^² = mv²+ kx²

so here v² will be

v² = k(A² - x²) / m

v = √[(k/m)×(A² - x²)] ............2

here x = (1/2)A so from from 2 equation

v = √[(k/m)×(A² - (A/2)²)]

v = √[(k/m)×(3/4×A²)]

now put all value

v = √[(12.5/ 77.3 × $10^{-3}$ )×(3/4×(38.9 × $10^{-2}$ )²)]

v = 3.546106 m / s

speed of the mass is 3.546106 m / s

6 0

3 years ago