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3 years ago

Rephrase the law of universal gravitation

1 answer:

5 0

The law of universal gravitation says that one object attracts every other object using a proportional force to the mass of the object.

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Through what angle in degrees does a 33 rpm record turn in 0.32 s?<br> 63°<br> 35°<br> 46°<br> 74°

Darina [25.2K]

Answer:

1 rev = 2(pi) rad pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

6 0

3 years ago

The distance versus this plot for a particular object shows a quadratic relationship. Which column of distance data is possible

SOVA2 [1]

Answer:

Explanation:

In Column A, the pattern is 1², 2², 3², etc. So x(t) = t², which is quadratic.

In Column B, the pattern is 2*1, 2*2, 2*3, etc. So x(t) = 2t, which is linear.

In Column C, the pattern is 9*1, 9*2, 9*3, etc. So x(t) = 9t, which is linear.

In Column D, the pattern is 1/1, 1/2, 1/3, etc. So x(t) = 1/t, which is reciprocal.

In Column E, the pattern is 1/1², 1/2², 1/3², etc. So x(t) = 1/t², which is reciprocal.

5 0

4 years ago

. A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up

Liula [17]

Answer:

p = -8 kg-m/s

Explanation:

Given that,

Initial speed of the rock, u = 8 m/s

Mass of the rock, m = 1 kg

The ball travels up to a maximum height, then returns to the ground.

We need to find the rock's momentum as it strikes the ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So

p = mv

p = 1 kg × (-8 m/s)

= -8 kg-m/s

So, the rock's momentum as it strikes the ground is (-8 kg-m/s).

5 0

3 years ago

A 0.2 kg hockey puck moving at 80 m/s is caught by a 40 kg goalie at rest. With what speed does the goalie slide on the slide?

Lady_Fox [76]

Answer:

V = 0.39 m/s

Explanation:

Given that,

Mass of hockey puck, m = 0.2 kg

Mass of goalie = 40 kg

Speed of hockey puck, v = 80 m/s

We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :

$mv=(M+m)V\\\\V=\dfrac{mv}{M+m}\\\\V=\dfrac{0.2\times 80}{0.2+40}\\\\V=0.39\ m/s$

So, the required speed is 0.39 m/s.

5 0

2 years ago

A 1.15 kg book is at rest on the table. What is the magnitude of the normal force that the table is exerting on the book?

Agata [3.3K]

Answer:

11.27N

Explanation:

Given parameters:

Mass of the book = 1.15kg

Unknown:

Magnitude of the normal force = ?

Solution:

The normal force is the vertical force exerted by a body on an object.

It can be described as the weight of an object.

Normal force = mass x acceleration due to gravity

Normal force = 1.15 x 9.8 = 11.27N

5 0

3 years ago