Answer:
The angular displacement is
Explanation:
From the question we are told that
The speed of the driver is
The acceleration of the driver is
The time taken is
The radius of the tire is
The distance covered by the car during this acceleration can be calculated using the equation of motion as follows
Now substituting values
Now the angular displacement of the car with respect to the tire movement can be represented mathematically as
substituting values
Answer: a) r= 4.82 * 10^-4 m ; b) 1420 V
Explanation: In order to solve this problem we have to take into account that potential for a sphere respec to V=0 at the infinity, which is given by:
V=k*Q/r where r is the radius of the drop
then we have
r=k*Q/V=9*10^9*38pC/710V= 4.82 * 10^-4 m
Finally if we join two drop to form one with the same radius but with twice charge the resultant potential is:
V= k*2*Q/(r)= 710*2= 1420 V
Answer: The mass of the sculpture is 11.8kg
Explanation:
Using the equation of fundamental frequency of a taut string.
f = (1/2L)*√(T/μ) .... (Eqn1)
Where
f= frequency in Hertz =80Hz
T = Tension in the string = Mg
M represent the mass of the substance (sculpture) =?
g= 9.8m/s^2
L= Length of the string=90cm=0.9m
μ= mass density = mass of string /Length of string
mass of string =5g=0.005kg
L=0.9m
μ=0.005/0.9 = 0.0056kg/m
Using (Eqn1)
80= 1/(2*0.9) √(T/0.0056)
144= √(T/0.0056)
Square both sides
20736= T/0.0056
T= 116.12N
Recall that T =Mg
116.12= M * 9.8
M=116.12/9.8
M= 11.8kg
Therefore the mass of the sculpture is 11.8kg
<u>Answer:</u>
• black hole - one of the most dense objects in the universe
• red giant - a very large star
• white dwarf - an old, very dense hot star that is cooling
• nebula - a mass of gas and dust