<span>a)
Capacitance = k x ε° x area / separation
ε° = 8.854 10^-12 F/ m
k = 2.4max
average k = 0.78 / 1.27 * 2.4 +(1.27- 0.78) / 1.27 * 1 = 1.474 + 0.386 = 1.86
(61.4 % separation k = 2.4 --- 38.6 % k = 1 air --- average k = 0.614 * 2.34 + 0.386 * 1 = 1.86
area = 145 cm2 = 0.0145 m2
separation = 1.27 cm 0.0127 m
C = 1.86 * 8.854 10^-12 * 0.0145 / 0.0127 = 18.8 pF
b) Q = C * V --- 18.8 * 83 = 1560.4 pC = 1.5604 nC
c) E = V / d = 83 / 0.0127 = 6535.4 V/m </span>
Answer:
<h3>The answer is 2.51 s</h3>
Explanation:
The time taken can be found by using the formula

d is the distance
v is the velocity
From the question we have

We have the final answer as
<h3>2.51 s</h3>
Hope this helps you
Answer:

Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as

8.0 m/s if there is no air resistance. (B)
Less if there IS any air resistance.
The first choices are correct, because the second choices could happen by things other than light.