The number of years that will pass before the radius of the Moon's orbit increases by 3.6 x 10^6 m will be 90000000 years.
<h3>How to compute the value?</h3>
From the information given, the orbit of the moon is increasing in radius at approximately 4.0cm/yr.
Therefore, we will convey the centimeters to meter. This will be 4cm will be:
= 4/100 = 0.04m/yr.
Time = Distance / Speed
Time = 3.6 x 10^6/0.04
Time = 90000000 years.
Learn more about moon on:
brainly.com/question/13262798
#SPJ1
Complete question:
Tidal friction is slowing the rotation of the Earth. As a result, the orbit of the moon is increasing in radius at approximately 4.0cm/y. Assuming this rate to be constant how many years will pass before the radius of the Moon's orbit increases by 3.6 x 10^6
Answer:
The image behind the mirror is called a virtual image because it cannot be projected onto a screen—the rays only appear to originate from a common point behind the mirror. If you walk behind the mirror, you cannot see the image, because the rays do not go there
Answer:
The speed will be "3.4×10⁴ m/s²".
Explanation:
The given values are:
Angular speed,
w = 7200 rpm
i.e.,
= 
= 
Speed from the center,
r = 6.0 cm
As we know,
⇒ Linear speed, 
On putting the estimated values, we get
Now,
Acceleration on disk will be:
⇒ 
A :-) for this question , we should apply
a = v - u by t
Given - u = -2 m/s
v = -10 m/s
t = 16 sec
Solution -
a = v - u by t
a = -10 - -2 by 16
a = -12 by 16
( cut 12 and 16 because 2 x 6 = 12 and
2 x 8 = 16 )
( cut 6 and 8 because 2 x 3 = 6 and
2 x 4 = 8 )
a = 3 by 4
a = 0.75 m/s^2
.:. The acceleration is 0.75 m/s^2.
