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kicyunya [14]
3 years ago
5

A split highway has a number of lanes for traffic. For traffic going in one direction, the radius for the inside of the curve is

half the radius for the outside. One car, car A, travels on the inside while another car of equal mass, car B, travels at equal speed on the outside of the curve. Which statement about resultant forces on the cars is correct? A) The force on A is half the force on B. B) The force on B is half the force on A. C) The force on A is four times the force on B. D) The force on B is four times the force on A. E) There is no net resultant force on either as long as they stay on the road while
Physics
1 answer:
Arte-miy333 [17]3 years ago
7 0
Cuál es tu pregunta
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The one that accurately describes the products of a reaction is : B. new substances that are present at the end of a reaction
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hope this helps
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3 years ago
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Choose the option below that best completes this sentence: when two circuit elements (e.g., light bulbs, resistors, etc.) are in
Likurg_2 [28]

When two circuit elements (e.g., light bulbs, resistors, etc.) are in PARALLEL, the voltage drop across each element must be the same. (choice-b)

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3 years ago
The surface tension of water was determuned in a laboratory by using the drop weight method. 100 drops were released from a bure
lana [24]

Answer:

The surface tension of the water is 6.278×10⁻² N/m

error = 13.65%

Explanation:

The surface tension of water is given by

$ \gamma = \frac{F}{L} $

Where F is the force acting on water and L is the length over which is force is acted.

We are given the mass of 100 droplets of water

M = 3.78 g

n = 100

The mass of 1 droplet is given by

m = \frac{M}{n} \\\\m = \frac{3.78}{100}\\\\m =  0.0378 \: g \\\\m = 3.780\times10^{-5} \: kg

The force acting on a single droplet of water is given by

F = m \cdot g

Where m is the mass of water droplet and g is the acceleration due to gravity

F = 3.780\times10^{-5} \cdot 9.81

F = 3.708\times10^{-4} \: N

The circumferential length of the droplet is given by

L = \pi \cdot d

Where d is the diameter

L = \pi \cdot 1.88\times10^{-3}\\\\L = 5.906 \times10^{-3} \: m

Now we can find out the required surface tension of the water

\gamma = \frac{3.708\times10^{-4} }{5.906 \times10^{-3}} \\\\\gamma = 0.06278\: N/m\\\\\gamma = 6.278 \times10^{-2} \: N/m\\\\

Therefore, the surface tension of the water is 6.278×10⁻² N/m

The tabulated value of the surface tension of water at 20 °C is given by

$ \gamma_t = 0.0727 \: N/m $

The percentage error between tabulated and calculated surface tension is given by

$ error = \frac{\gamma_t - \gamma }{\gamma_t} $

$ error = \frac{ 0.0727 - 0.06278}{0.0727} \times 100\% $

$ error = 13.65 \%

7 0
3 years ago
You raise a bucket of water from the bottom of a well that is 12 m deep. the mass of the bucket and the water is 5.00 kg, and it
MArishka [77]
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What is the relative size and composition of the universe, a galaxy, and a solar system?
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2 years ago
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