Question

A pressure of 7x10^5N/m is applied to all surfaces of a copper cube (of sides 25 cm) what is the fractional change in volume of a cube? ( for copper B= 14x10^10N/m)

Answer 1

Answer:

The correct solution is "$5\times 10^{-4}$ %".

Explanation:

The given values are:

Pressure,

$\Delta P=7\times 10^5 \ N/m$

for copper,

$B=14\times 10^{10} \ N/m$

As we know,

The Bulk Modulus (B) = $\frac{\Delta P}{-\frac{\Delta V}{V} }$

or,

The decrease in volume will be:

= $(\frac{\Delta V}{V})\times 100 \ percent$

then,

= $\frac{\Delta P}{B}\times 100 \ percent$

On putting the values, we get

= $\frac{7\times 10^5}{14\times 10^{10}}\times 100 \ percent$

= $5\times 10^{-4} \ percent$