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nlexa [21]
3 years ago
12

Which resonance structure would most likely create the infrared (IR) spectrum for the equilibrium geometry calculation of SCN −

SCN− in Part F.1? both resonance stuctures [ S − C ≡ N ] − [S−C≡N]− neither resonance structure [ S = C = N ] −
Chemistry
1 answer:
rjkz [21]3 years ago
3 0

Answer:

Resonance Structures for SCN-:[S-C N]-

Resonance StructureEnergy (kJ/mol)[S-C N]--23.00[S=C=N]

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The 38 elements in groups 3 through 12 of the periodic table are called "Alkaline Earth Metals" O True O False​
kotykmax [81]

Answer:

FALSE

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5 0
3 years ago
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What is the index of hydrogen deficiency of a compound with a molecular formula of c6h15n?
7nadin3 [17]

Answer:

IHD = 0

Explanation:

Given that

C₆H₁₅N

Number of carbon atoms(n) = 6

Number of hydrogen atoms(x') = 15

Number of nitrogen atoms = 1

There is nitrogen atoms then x = x' -1

The index of hydrogen deficiency given as

IHD=\dfrac{2n+2-x}{2}

So

IHD=\dfrac{2n+2-x}{2}

IHD=\dfrac{2\time 6+2-(15-1)}{2}

IHD = 0

The index of hydrogen deficiency is zero.

6 0
3 years ago
Be sure to answer all parts. Styrene is produced by catalytic dehydrogenation of ethylbenzene at high temperature in the presenc
svlad2 [7]

Answer:

a) ΔHºrxn = 116.3 kJ, ΔGºrxn = 82.8 kJ,  ΔSºrxn =  0.113 kJ/K

b) At 753.55 ºC or higher

c )ΔG =  1.8 x 10⁴ J

    K = 8.2 x 10⁻²

Explanation:

a)                                 C6H5−CH2CH3  ⇒  C6H5−CH=CH2  + H₂

ΔHf kJ/mol                    -12.5                           103.8                      0

ΔGºf kJ/K                        119.7                         202.5                      0

Sº J/mol                          255                          238                      130.6*

Note: This value was not given in our question, but is necessary and can be found in standard handbooks.

Using Hess law to calculate  ΔHºrxn we have

ΔHºrxn  = ΔHfº C6H5−CH=CH2 +  ΔHfº H₂ - ΔHºfC6H5−CH2CH3

ΔHºrxn =     103.8 kJ + 0 kJ  - (-12.5 kJ)

ΔHºrxn = 116.3 kJ

Similarly,

ΔGrxn = ΔGºf C6H5−CH=CH2 +  ΔGºfH₂ - ΔGºfC6H5CH2CH3

ΔGºrxn=   202.5 kJ + 0 kJ - 119.7 kJ  = 82.8 kJ

ΔSºrxn = 238 J/mol + 130.6 J/mol -255 J/K = 113.6 J/K = 0.113 kJ/K

b) The temperature at which the reaction is spontaneous or feasible occurs when ΔG becomes negative and using

ΔGrxn =  ΔHrxn -TΔS

we see that will happen when the term  TΔS  becomes greater than ΔHrxn since ΔS  is positive  , and so to sollve for T we will make ΔGrxn equal to zero and solve for T. Notice here we will make the assumption that  ΔºHrxn and ΔSºrxn remain constant at the higher temperature  and will equal the values previously calculated for them. Although this assumption is not entirely correct, it can be used.

0 = 116 kJ -T (0.113 kJ/K)

T = 1026.5 K  =  (1026.55 - 273 ) ºC = 753.55 ºC

c) Again we will use

                       ΔGrxn =  ΔHrxn -TΔS

to calculate ΔGrxn   with the assumption that ΔHº and ΔSºremain constant.

ΔG =  116.3 kJ - (600+273 K) x 0.113 kJ/K =  116.3 kJ - 873 K x 0.113 kJ/K

ΔG =  116.3 kJ - 98.6 kJ =  17.65 kJ = 1.8 x 10⁴ J ( Note the kJ are converted to J to necessary for the next part of the problem )

Now for solving for K, the equation to use is

ΔG = -RTlnK and solve for K

- ΔG / RT = lnK  ∴ K = exp (- ΔG / RT)

K = exp ( - 1.8 x 10⁴ J /( 8.314 J/K  x 873 K)) = 8.2 x 10⁻²

8 0
2 years ago
What does Gibbs free energy depend on? O A. It depends on the rate and quantity of the reaction. O B. It depends on the activati
Oksana_A [137]

Answer:

C: It depends on the entropy and enthalpy of the reaction.

Explanation:

Gibbs free energy is defined as the maximum amount of non-expansion work that can be gotten from a closed system. Now this work is usually done in place of the system’s internal energy and Energy that is not extracted as work is usually exchanged with the immediate surroundings in the form of heat.

5 0
2 years ago
A sample of a compound contains 3.21 g of sulfur and 11.4 g of fluorine. Which of the following represents the empirical formula
Sergeeva-Olga [200]

Answer:

The empirical formula is SF6 (option E)

Explanation:

Step 1: Data given

Mass of sulfur = 3.21 grams

Mass of fluorine = 11.4 grams

Molar mass sulfur = 32.065 g/mol

Molar mass fluorine = 19.00 g/mol

Step 2: Calculate moles

Moles = mass /molar mass

Moles sulfur = 3.21 grams / 32.065 g/mol

Moles sulfur = 0.100 moles

Moles fluorine = 11.4 grams / 19.00 g/mol

Moles fluorine = 0.600 moles

Step 3: Calculate mol ratio

We divide by the smallest amount of moles

S: 0.100 / 0.100 = 1

F : 0.600 / 0.100 = 6

The empirical formula is SF6 (option E)

7 0
3 years ago
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