From the reactions, 1.04 g of H2 and 7.995 g of aluminum phosphate is produced.
<h3>What is stoichiometry?</h3>
The term stoichiometry has to do with the amount of substances that participates in a reaction.
For reaction 1;
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg reacted = 12.5 g/24g/mol = 0.52 moles
If 1 mole of Mg produced 1 mole of H2
0.52 moles produces 0.52 moles of H2
Mass of H2 = 0.52 moles * 2 g/mol = 1.04 g
For reaction 2;
2Li3PO4 + Al2(SO4)3 → 3Li2SO4 + 2AIPO4
Number of moles of lithium phosphate = 7.5 g/116 g/mol = 0.065 moles
2 moles of Li3PO4 produced 2 moles of AIPO4
0.065 moles of Li3PO4 produced 0.065 moles of AIPO4
Mass of AIPO4 = 0.065 moles * 123 g/mol = 7.995 g
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ANSWER

EXPLANATION
Given that;
The two reactants are KBr and CaO
Double replacement reaction is a type of chemical reaction that occur when two reactants exchange cations and anions to yield new products.

Therefore, the resulting products of the given data are K2O + CaBr2
The correct answer is option B
Solubility data of a certain solute with a certain solvent is empirical. There are constant values for this at varying temperatures. For KCl in water at 25°C, the solubility is 35.7 g/100 mL of water. When you compare this with the solubility data of KCl with ethanol, this means that KCl is more soluble in water than in ethanol. This is true because KCl is an ionic salt which is very soluble in water.
Answer:
50
Explanation:
We will need a balanced equation with masses, moles, and molar masses of the compounds involved.
1. Gather all the information in one place with molar masses above the formulas and masses below them.
Mᵣ: 30.01 32.00 46.01
2NO + O₂ ⟶ 2NO₂
Mass/g: 80.00 16.00
2. Calculate the moles of each reactant

3. Calculate the moles of NO₂ we can obtain from each reactant
From NO:
The molar ratio is 2 mol NO₂:2 mol NO

From O₂:
The molar ratio is 2 mol NO₂:1 mol O₂

4. Identify the limiting and excess reactants
The limiting reactant is O₂ because it gives the smaller amount of NO₂.
The excess reactant is NO.
5. Mass of excess reactant
(a) Moles of NO reacted
The molar ratio is 2 mol NO:1 mol O₂

(b) Mass of NO reacted

(c) Mass of NO remaining
Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO