Can somebody plz help answer this question correctly (only if u know how to do it) thanks :3
1 answer:
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Answer: Equilibrium concentration of at
is 4.538 M
Explanation:
Initial concentration of = 0.056 M
Initial concentration of = 4.60 M
The given balanced equilibrium reaction is,
Initial conc. 0.056 M 4.60 M 0 M 0 M
At eqm. conc. (0.056-x) M (4.60-2x) M (x) M (6x) M
The expression for equilibrium constant for this reaction will be,
Given : equilibrium concentration of =x = 0.031 M
Concentration of = (4.60-2x) M =
=4.538 M
Thus equilibrium concentration of at
is 4.538 M
Answer : The energy removed must be, 29.4 kJ
Explanation :
The process involved in this problem are :
The expression used will be:
where,
= heat released for the reaction = ?
m = mass of benzene = 94.4 g
= specific heat of solid benzene =
= specific heat of liquid benzene =
= enthalpy change for fusion =
Now put all the given values in the above expression, we get:
Negative sign indicates that the heat is removed from the system.
Therefore, the energy removed must be, 29.4 kJ