Answer:
A(t) = 160 - 130 e^(-t/40)
Explanation:
At the start, the tank contains A(0) = 30 g of salt.
Salt flows in at a rate of
(1 g/L) * (4 L/min) = 5 g/min
and flows out at a rate of
(A(t)/160 g/L) * (4 L/min) = A(t)/40 g/min
so that the amount of salt in the tank at time t changes according to
A'(t) = 4 - A(t)/40
Solve the ODE for A(t):
A'(t) + A(t)/40 = 4
e^(t/40) A'(t) + e^(t/40)/40 A(t) = 4e^(t/40)
(e^(t/40) A(t))' = 4e^(t/40)
e^(t/40) A(t) = 160e^(t/40) + C
A(t) = 160 + Ce^(-t/40)
Given that A(0) = 30, we find
30 = 160 + C
C = -130
so that the amount of salt in the tank at time t is
A(t) = 160 - 130 e^(-t/40)
Permanent modular construction tends to fit the construction purposes that it was specifically designed for.
Answer:
Four types of gas turbine engines are used to propel and power aircraft. They are the turbojet, turbofan, turboprop, and turboshaft.
Answer:
critical stress = 595 MPa
Explanation:
given data
fracture toughness = 74.6 MPa-
crack length = 10 mm
f = 1
solution
we know crack length = 10 mm
and crack length = 2a as given in figure attach
so 2a = 10
a = 5 mm
and now we get here with the help of plane strain condition , critical stress is express as
critical stress = ......................1
put here value and we get
critical stress =
critical stress = 595 MPa
so here stress is change by plane strain condition because when plate become thinner than condition change by plane strain to plain stress.
plain stress condition occur in thin body where stress through thickness not vary by the thinner section.