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velikii [3]
3 years ago
6

Tech A says that over time a grease seal can wear a groove in the sealing surface of the axle or shaft. Tech B says that grease

seals need to be replaced every time the bearing is removed. Who is correct?
Engineering
2 answers:
Natasha_Volkova [10]3 years ago
7 0

Answer:

Tech A is correct

Explanation:

Tech A is correct because overtime a grease seal can wear a groove in the sealing surface of the axle or shaft. Most times, worn out or damaged bearings can wear a groove into the axle shaft. The seal may also wear a groove into the axle shaft. Anytime this becomes the case, it's very important to replace the axle shaft assembly, bearings and seal.

Tech B is correct but to an extent, because there is a way the bearings will be removed carefully so replacements of grease seals won't be needed which makes tech B somehow wrong

maw [93]3 years ago
7 0

Answer:

Tech A is correct

Explanation:

Over time a grease seal in an axle or shaft, which is having continuous pinion seal failure due to leaks, can have worn a groove in the sealing surface.

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Using the background information provided and your answers to questions 1 & 2, look at the hex packet below and identify the
yanalaym [24]

Answer:

Goal address: Based on the above Ethernet outline design, we get that the goal address begins from the first hex worth and is of size 12 hex values (got from question 1). In light of the bundle given, we get that the goal address is 6c40 0889 c448.  

Source address: Similarly, the source address begins after the goal address and is of size 12 hex values (got from question 1). Thus, the appropriate response is f832 e4a7 fb38.  

Type/Length: The sort/length begins after the source address and is of size 4 hex values (got from question 1). Thus, the appropriate response is 0806.  

Data (Payload): The data(payload) begins after the sort/length and finishes not long before FCS(Checksum) which is of 4 bytes for example 4 * 2 = 8 hex qualities. So the information comprises of everything between the 'type/length' and 'CRC'. We persuade the CRC to be c0a8 01f2. Henceforth, the appropriate response is 0001 0800 0604 0002 f832 e4a7 bf38 c0a8 0101 6c40 0889 c448.  

Question 4:  

The Ethernet parcel type characterizes the convention utilized for sending the bundle information. We realize that type 0x0800 demonstrates the IPv4 convention, 0x0806 shows an ARP convention, and 0x86DD demonstrates an IPv6 convention. In light of the appropriate response we got in Question 3, we realize that the sort/length esteem for the given parcel is 0806, which implies that convention utilized for sending the information bundle was ARP convention.

8 0
3 years ago
T he area of a circle is pr 2. Define r as 5, then find the area of a circle,using MATLAB®.(b) The surface area of a sphere is 4
aksik [14]

Answer:

Area of Circle = 78.5398

Surface Area of Sphere =  1.2566 x 10^3 = 1256.6 ft

Volume of Sphere =  33.5103 ft

Explanation:

Please find below the written MatLab script used to solve the problem. I had to define r in each case to solve for the Area of the circle, the surface area and the volume of the Sphere.

r=5; % define r as 5

a=pi*r^2;% calculate the area of the circle

AreaOfCircle=a

r=10; % define r and 10 ft

sa=4*pi*r^2; %Calculate the surface area of the sphere

SphereSurfaceArea=sa

r=2;% define r as 2 ft

vs=(4/3)*pi*r^3;% Calculate the volume of the sphere

VolumeShere=vs

3 0
3 years ago
Read 2 more answers
External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter o
sveticcg [70]

Answer:

The correct answer is "K_c=6.0369 \ MPa\sqrt{m}".

Explanation:

Given:

Maximum load,

P = 50,000 N

Crack length,

a = 3mm

or,

  = 3×10⁻³ m

Diameter,

d = 32 mm

As we know,

⇒  Maximum stress, \sigma=\frac{P}{A}

                                      =\frac{50000}{(\frac{\pi}{4}\times 32^2)}

                                      =62.20 \ N/mm^2

Now,

⇒  Fracture tougness, K_c=Y \sigma\sqrt{\pi a}

On substituting the values, we get

                                           =1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}

                                           =6.0369 \ MPa\sqrt{m}

4 0
3 years ago
Choose the true statement from those shown below: A Merchant Account allows you to use SSL on your web site. Disadvantages of us
Slav-nsk [51]

Answer:

The answer is A. that is, a merchant account allows you to use SSL on your website.

Explanation:

SSL means Secure Sockets Layer and this is an encryption-based Internet security protocol.

For an e-commerce merchant website or account, it is advised that an SSL package be installed to prevent any potential loss of private information.

For this reason, a merchant account allows use of SSL on your website because this also boost the confidence of client and customers visiting the website to purchase products.

7 0
3 years ago
The polycarbonate shell functions as all of the following except:
krok68 [10]

Answer:

what are the answers expect what?

Explanation:

Polycarbonate is commonly used in eye protection, as well as in other projectile-resistant viewing and lighting applications that would normally indicate the use of glass, but require much higher impact-resistance. Polycarbonate lenses also protect the eye from UV light.

6 0
3 years ago
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