Answer:
a. Using a straight forward scheme, the RC4 algorithm stores 2064 bits in the interval state.
b. 1700 bits
Explanation:
See RC4 Algorithm attached with details
Explain 4 things you can do with a Combination Square
1 answer:
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Answer:
the pressure at the end of the combustion is 2.68 MPa
Solution:
As per the question:
Initial Pressure, P = 0.95\ MPa
Temperature before combustion, = 273 + 425 = 698 K
Temperature after combustion, = 1973 K
Now,
To calculate the pressure at the end of combustion, P':
By using the Pressure-Temperature relation from Gay- Lussac's law:
Answer:
Check the explanation
Explanation:
Main1.java
import java.lang.InterruptedException;
import java.lang.Thread;
import java.util.Random;
public class Main {
final private static int FARMERS = 10;
public static void main(String[] args) {
Bridge bridge = new Bridge();
Random r = new Random();
System.out.println("Running with " + FARMERS + " farmers...");
// Enter a bunch of farmers from different directions.
for (int i = 0; i < FARMERS; i++) {
Farmer farmer;
if (r.nextBoolean()) {
farmer = new SouthBoundFarmer(bridge);
} else {
farmer = new NorthBoundFarmer(bridge);
}
cross(farmer);
}
}
private static void cross(Farmer f) {
new Thread(f).start();
}
}
SouthBoundFarmer.java
public class SouthBoundFarmer extends Farmer {
public SouthBoundFarmer(Bridge b) {
super(b);
this.name = "South";
}
}
Farmer.java
import java.lang.InterruptedException;
import java.util.Random;
public class Farmer implements Runnable {
private Bridge bridge;
private Random random;
protected String name;
public Farmer(Bridge b) {
this.bridge = b;
this.random = new Random();
}
public void crossBridge(Bridge bridge) {
System.out.println("[" + this.name + "] Waiting to enter bridge...");
try {
bridge.enter();
System.out.println("[" + this.name + "] Entering bridge...");
// Crossing bridge...some farmers are fast, others are slow :P
Thread.sleep(1000 + random.nextInt(9000));
System.out.println("[" + this.name + "] Leaving bridge...");
} catch (InterruptedException e) {
System.out.println("...Interrupted!");
} finally {
bridge.leave();
}
}
public void run() {
this.crossBridge(this.bridge);
}
}
Bridge.java
import java.lang.InterruptedException;
import java.util.concurrent.Semaphore;
public class Bridge {
private Semaphore lock;
public Bridge() {
this.lock = new Semaphore(1);
}
public void enter() throws InterruptedException {
this.lock.acquire();
}
public void leave() {
this.lock.release();
}
}
NorthBoundFarmer.java
public class NorthBoundFarmer extends Farmer {
public NorthBoundFarmer(Bridge b) {
super(b);
this.name = "North";
}
}
KINDLY CHECK THE OUTPUT BELOW :
Answer:
Δp = ∫
Explanation:
The pressure drop formula is given above. It determines the relation between pressure drop per unit along with smooth walled channel. The formula is from Buckingham pi theorem in which repeating and non repeating variables are used together.