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Helga [31]
3 years ago
11

An organization sets its standards for quality according to the best product it can produce.

Engineering
2 answers:
Marianna [84]3 years ago
6 0
I believe it’s True, but please correct me if I’m wrong!
dusya [7]3 years ago
5 0

Answer:

True!! took the test

Explanation:

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Successful students read on a ____ basis.
icang [17]

I think it is daily????

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Info security:
il63 [147K]

Answer:

True

Explanation:

Dual home host - it is referred to as the firewall that is incorporated with two or more networks. out of these two networks, one is assigned to the internal network and the other is for the network. The main purpose of the dual-homed host is to ensure that no Internet protocol traffic is induced between both the network.

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Can you gift points in this if yes please send some
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4 years ago
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Which of the following is NOT an ASE certification? Select one:
stiks02 [169]

The option that is not an ASE certification is . A/C and Refrigerants handling certification (609).

<h3>What is ASE certification?</h3>

The term ASE is known to be a body that tends to promotes excellence in regards to vehicle repair, service as well as parts distribution.

Note that in the world today more than a quarter of  million of people are known to possess ASE certifications.

Since ASE Certified professionals work in in all areas of the transportation industry. one can say that The option that is not an ASE certification is. A/C and Refrigerants handling certification (609).

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8 0
2 years ago
If an object is near the surface of the earth the variation of its weight with distance from the center of the earth can ofteb b
zalisa [80]

Answer:

h=32.1 km

Explanation:

<em>solution:</em>

using newton law of gravitational attraction and newton second law:

W=\frac{Gmm_{E} }{r^{2} } \\a=\frac{Gm_{E}}{r^{2}} \\W=ma\\

m_{E}= mass of earth

r= distance between two masses

at sea level

a=g

r=R_{E}

a=\frac{Gm_{E}}{r^{2}}.............................(1)

Gm_{E} =gR_{E}^2.........................(2)

by substituting (2) and (1) a=g\frac{R_{E}^2 }{r^{2} } acceleration due to gravity at a distance r from the centre of the earth in terms of g (sea level)

so the weight of the object at a distance r from the centre of the earth (W=ma)

W=mg(Re^2/r^2)..........(3)

h the height above the surface of the earth: r=Re+h

putting the value of r in eq (3)

W=mg(Re/Re+h)^2

W=0.99 mg

solving for height h:

h=Re(1/√0.99)-(1))

h=32.1 km

4 0
3 years ago
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