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DedPeter [7]
3 years ago
11

An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign

al at that point is 320 mV/m. Assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. The magnetic field amplitude of the signal at that point, in nT, is closest to:
Physics
1 answer:
hammer [34]3 years ago
3 0

Answer:

1.07 nT

Explanation:

We know that E/B = c where E = electric field amplitude = 320 mV/m = 0.32 V/m, B = magnetic field amplitude and c = speed of light = 3 × 10⁸ m/s.

So, B = E/c

Substituting E and c into B, we have

B = E/c

= 0.32 V/m ÷ 3 × 10⁸ m/s

= 0.1067 × 10⁻⁸ T

= 1.067 × 10⁻⁹ T

= 1.067 nT

≅ 1.07 nT

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A 2.00-kg object A is connected with a massless string across a massless, frictionless pulley to a 3.00-kg object B. Object A re
slamgirl [31]

Answer:

  • tension: 19.3 N
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Explanation:

<u>Given</u>

  mass A = 2.0 kg

  mass B = 3.0 kg

  θ = 40°

<u>Find</u>

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  The acceleration of the masses

<u>Solution</u>

Mass A is being pulled down the inclined plane by a force due to gravity of ...

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The tension in the string, T, is such that the net force on each mass results in the same acceleration:

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  (T -12.59806 N)/(2 kg) = (29.4 N -T) N/(3 kg)

  T = (2(29.4) +3(12.5986))/5 = 19.3192 N

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The string tension is about 19.3 N; the acceleration of the masses is about 3.36 m/s^2.

3 0
3 years ago
You run<br> completely around a 400m track in<br> 80s. What was your average velocity?
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Answer:

V=?

S=400m

t=80s

V=S/t

V=400/80

V=5m/sec

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3 years ago
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It's going down.

Hope this helps you
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If an object has 180 J of PE and a mass of .5kg, what is its height?
Nonamiya [84]
PE=mgh
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180=5h
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3 years ago
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