An 800 kHz radio signal is detected at a point 3.2 km distant from a transmitter tower. The electric field amplitude of the sign
1 answer:
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Answer:
150000000
49050000 N/C
Explanation:
q = Charge = 24 pC
m = Mass of honeybee = 0.12 g
E = Electric field = 100 N/C
g = Acceleration due to gravity = 9.81 m/s²
Number electrons is
The number of electrons added or removed was 150000000
Force is given by
The ratio is
The ratio is
Balancing the forces we get
The electric field required is 49050000 N/C
Answer:
λ = 451.7 nm
Explanation:
The expression for the constructive interference of the double diffraction experiment is
d sin θ = m λ
let's use trigonometry
tan θ = y / L
how the experiment occurs at very small angles
tan θ = sin θ / cos θ = sin θ
sin θ = y / L
we substitute
d y / L = m λ
λ =
let's calculate
λ =
λ = 4.51699 10⁻⁷ m
λ = 4.517 10⁻⁷ m (109 nm / 1m)
λ = 451.7 nm
Answer:
The appropriate response will be "Length must be increased by 0.012%".
Explanation:
The given values is:
ΔT = 5 s/day
Now,
⇒
On multiplying both sides by "100", we get
⇒
⇒ (%)
∵
On substituting the values, we get
⇒ % =
%
On applying cross multiplication, we get
⇒ % =
%
⇒ =
⇒ =
⇒ = %