Answer:
Partial pressure of H₂ is 0.375 atm
Explanation:
We apply the mole fraction to solve this.
Standard pressure is 1 atm
Mole fraction of a gas = Moles of gas / Total moles
Mole fraction of pressure = Partial pressure of gas / Total pressure
Both values are the same
Total moles = 4 moles of O₂ + 3 moles of H₂ and 1 mol of N₂ = 8 moles
3 moles H₂ / 8 moles = Partial pressure H₂ / 1 atm
(3 / 8 ) .1 = 0.375 atm → Partial pressure of H₂
You can harm ur self if you dont know variables . Bcs the values of variables should limit.
Answer:
The answer to your question is 178.6 g
Explanation:
Data
ΔT = 1.8 °C
mass = 17.5 g
mass of water = 100 g
Kc = 1.86
Process
1.- Calculate the molality using the following formula
ΔTc = mKc
solve for m
m = ΔTc/Kc
substitution
m = 1.8/1.86
result
m = 0.968
2.- Calculate the number of moles
m = # of moles/kg of solvent
kg of solvent = 0.1 kg
# of moles = m x kg of solvent
# of moles = 0.968 x 0.1
# of moles = 0.0968
3.- Calculate the molar mass
x g molar mass --------------------- 1 mol
17.5 g --------------------- 0.0968 moles
x = (1 x 17.5)/0.0968
x = 178.6 g
The law of conservation of energy states that energy can neither be created nor destroyed.
It can only be converted from one form of energy to another.
I hope this helps! ❤️
