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jeyben [28]
3 years ago
7

A chicken crosses a 7.50 m wide road at a constant speed of 0.367 m/s. How much time does it take to cross (in seconds)?

Physics
2 answers:
mars1129 [50]3 years ago
7 0
<h3><u>Answer;</u></h3>

= 20.436 seconds

<h3><u>Explanation;</u></h3>

Speed = Distance × time

Therefore;

Time = Distance/speed

Distance = 7.50 m, speed = 0.367 m/s

Time = 7.50/0.367

         <u>= 20.436 seconds </u>

Airida [17]3 years ago
6 0

Answer:

Time taken by it is 20.43 seconds.

Explanation:

It is given that,

Distance covered by the chicken, d = 7.5 m

Speed of the chicken, v = 0.367 m/s

We need to find the time taken to cross. Time taken by an object is given by :

t=\dfrac{d}{v}

t=\dfrac{7.5\ m}{0.367\ m/s}

t = 20.43 s

So, the time taken by it to cross the road is 20.43 seconds. Hence, this is the required solution.

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Let’s say I am in a bumper car and have a velocity of 14 m/s, driving in the positive x-direction. I and my bumped car have a ma
AlekseyPX

Answer:

160 kg

12 m/s

Explanation:

m_1 = Mass of first car = 120 kg

m_2 = Mass of second car

u_1 = Initial Velocity of first car = 14 m/s

u_2 = Initial Velocity of second car = 0 m/s

v_1 = Final Velocity of first car = -2 m/s

v_2 = Final Velocity of second car

For perfectly elastic collision

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}\\\Rightarrow m_2v_2=m_{1}u_{1}+m_{2}u_{2}-m_{1}v_{1}\\\Rightarrow m_2v_2=120\times 14+m_2\times 0-(120\times -2)\\\Rightarrow m_2v_2=1920\\\Rightarrow m_2=\frac{1920}{v_2}

Applying in the next equation

v_2=\frac{2m_1}{m_1+m_2}u_{1}+\frac{m_2-m_1}{m_1+m_2}u_2\\\Rightarrow v_2=\frac{2\times 120}{120+\frac{1920}{v_2}}\times 14+\frac{m_2-m_1}{m_1+m_2}\times 0\\\Rightarrow \left(120+\frac{1920}{v_2}\right)v_2=3360\\\Rightarrow 120v_2+1920=3360\\\Rightarrow v_2=\frac{3360-1920}{120}\\\Rightarrow v_2=12\ m/s

m_2=\frac{1920}{v_2}\\\Rightarrow m_2=\frac{1920}{12}\\\Rightarrow m_2=160\ kg

Mass of second car = 160 kg

Velocity of second car = 12 m/s

5 0
3 years ago
A person wants to fire a water balloon cannon such that it hits a target 100m100m away. if the cannon can only be launched at 45
vladimir2022 [97]
<span>31.3 m/s Since the water balloon is being launched at a 45 degree angle, the horizontal and vertical speeds will be identical. Also the time the balloon takes to reach its peak altitude will match the time it takes to fall. So let's create a few expressions about what we know. Distance the water balloon travels at velocity v for time t d = vt Total time required for the entire trip is double since the balloon goes up, then goes down t = 2v/a Now let's plug in the numbers we have, assuming the acceleration due to gravity is 9.8 m/s^2 t = 2v/9.8 100 = vt Substitute 2v/9.8 for t in the 2nd formula 100 = v(2v/9.8) Solve for v. 100 = v(2v/9.8) 100 = 2v^2/9.8 980. = 2v^2 490 = v^2 22.13594 = v So we now know that both the horizontal velocity and vertical velocity needed is 22.13594 m/s. Let's verify that 2*22.13594 / 9.8 = 4.51754 So it will take 4.51754 second for the balloon to hit the ground after being launched. 4.51754 * 22.13594 = 100 And during that time it will travel 100 meters horizontally. But we need to know the total velocity. And the Pythagorean theorem comes to the rescue. Just square the 2 velocities, add them together, and take the square root. We already know the square is 490 from the work above, so sqrt(490+490) = sqrt(980) = 31.30495 m/s</span>
3 0
3 years ago
Which TWO statements describe behaviors of particles that are related to the
kolezko [41]

Answer: 1: (A) They allow electrons to move freely between them. 2: (C) they change their positions relative to one another.

Explanation:

7 0
2 years ago
A student walks 3 blocks east, 4 blocks north, and 3 blocks west. What is the displacement of the student?
12345 [234]
4 blocks north because he is it not asking for north east 
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3 years ago
Mark all the mesons a) Proton b) Electron c)Anti-top d) Gluon e) Tau Neutrino
Sloan [31]

Answer:

None

Explanation:

Subatomic particles are the particles which are very smaller than the atoms. Elementary particles are the examples of subatomic particles.

Elementary particles are the particles without any sub-structure which means they are not composed of other particles.

The elementary particles are classified into three categories which are discussed below:

(1) Quarks: up, down, top, bottom, strange, and charm.

(2) Leptons: muon, muon neutrino, electrons, electron neutrino,  tau, tau neutrino.

(3) Bosons:  Z bosons, W bosons, Higgs, Gluon, photons.

Mesons are the particles which compose one quark and one anti quarks.

Therefore, in the given list there is no meson.

3 0
3 years ago
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