Answer:
1200 J
Explanation:
From the question
K.E = 1/2mv²...................... Equation 1
Where K.E = Kinetic Energy, m = mass of the rod, v = velocity of the rod
But
V = ωr..................... Equation 2
Where ω = angular velocity of the rod, r = radius of the rod.
Substitute equation 2 into equation 1
K.E = 1/2m(ωr)²..................... Equation 3
Given: m = 60 kg, ω = 10 rad/s, r = 2 m
Substitute these values into equation 3
K.E = 1/2(6)(10×2)²
K.E = 3×(20)²
K.E = 3×400
K.E = 1200 J
